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photoshop1234 [79]
3 years ago
5

Find the m BD, given: mZCPA= 42, ZFPC = 90°

Mathematics
1 answer:
drek231 [11]3 years ago
8 0
Gegeheheehhwjwjwjwjwjwhwjwjehebwbebebebebebebee
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Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin
Alex787 [66]

Solution :

Given the equation :

$y = x^2 - 6x+3 $

$y=1(x^2 - 6x +n)+3$

$n = \left(\frac{b}{2}\right)^2$

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n = 9

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Therefore the vertex form of $y = x^2 - 6x+3 $  is  $y=1(x-3)^2- 6$.

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Step-by-step explanation:

if you didn't get that its 2 ( 1 + x )  ( 1 − x ) as the numerator and  x ^2 as the denominator

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