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2 years ago

15

Please helpp!! I neeeed help!!!!!

2 answers:

Over [174]2 years ago

6 0

Answer:

C

Step-by-step explanation:

Serhud [2]2 years ago

3 0

-783(1.05) i think i can barely see it

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How has the Roaring Twenties been portrayed in modern media?

Alexus [3.1K]

Answer:

The nation's total wealth more than doubled between 1920 and 1929, and this economic growth swept many Americans into an affluent but unfamiliar “consumer society.” People from coast to coast bought the same goods (thanks to nationwide advertising and the spread of chain stores), listened to the same music

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2 years ago

Y = 5x - 8<br><br> 4x + 3y = 33 el valor de x es ?

iren2701 [21]

Yo pienso que tu respuesta es

x =3, y =7

.

7 0

2 years ago

Help!!!!!!!!!!!!!!!!

deff fn [24]

502.5 = -502.5

Now

x = -502.5

= -5025/10

= -1005/2 feet

Answered by Gauthmath must click thanks and mark brainliest

3 0

2 years ago

Read 2 more answers

Suppose you are given either a fair dice or an unfair dice (6-sided). You have no basis for considering either dice more likely

hoa [83]

Answer: Our required probability is 0.83.

Step-by-step explanation:

Since we have given that

Number of dices = 2

Number of fair dice = 1

Probability of getting a fair dice P(E₁) = $\dfrac{1}{2}$

Number of unfair dice = 1

Probability of getting a unfair dice P(E₂) = $\dfrac{1}{2}$

Probability of getting a 3 for the fair dice P(A|E₁)= $\dfrac{1}{6}$

Probability of getting a 3 for the unfair dice P(A|E₂) = $\dfrac{1}{3}$

So, we need to find the probability that the die he rolled is fair given that the outcome is 3.

So, we will use "Bayes theorem":

$P(E_1|A)=\dfrac{P(E_1)P(A|E_1)}{P(E_1)P(A|E_1)+P(E_2)P(A|E_2)}\\\\(E_1|A)=\dfrac{0.5\times 0.16}{0.5\times 0.16+0.5\times 0.34}\\\\P(E_1|A)=0.83$

Hence, our required probability is 0.83.

8 0

3 years ago

How do I do this?need help

Lelu [443]

I have no clue at all

8 0

2 years ago