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3 years ago

To start, draw a ray with endpoint V. Construct VW (Line Segment) so that VW = 2PS

Mathematics

1 answer:

grin007 [14]3 years ago

3 0

You just want to draw a line that is twice as long as the one given. The end points should be labeled V and W.

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At how many points does the graph of function below intercept the

anastassius [24]

Answer:

C. 0

Step-by-step explanation:

The points of intercection between the graph of a quadratic function of the form $ax^{2} +bx+c$ are given by the discriminant of the quadratic formula.

Remember that the quadratic formula is:

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac } }{2a}$

The discriminant of he quadratic formula is just the thing inside the radical, in other words:

$discriminant=b^{2} -4ac$

- If the discriminant is negative, the graph of the quadratic function doesn't intercept the x-axis.

- If the discriminant is positive, the graph of the quadratic function intercept the x-axis at 2 points.

- If the discriminant is 0, the graph of the quadratic function intercept the x-axis at 1 point.

We can infer form our quadratic that $a=4$ , $b=-9$ , and $c=9$ , so let's replace the values in the discriminant:

$discriminant=b^{2} -4ac$

$discriminant=(-9)^{2} -4(4)(9)$

$discriminant=81-144$

$discriminant=-63$

Since the discriminant is negative, we can conclude that the graph of the quadratic function doesn't intercept the x-axis at any point.

3 0

3 years ago

Abby has 36 toy animal in 4 equal groups how many toy animals are there in?

dusya [7]

9 animals are in each group.

3 0

3 years ago

Read 2 more answers

If the sinø=7/12, what is cosø?

777dan777 [17]

Answer:

If the sinø=7/12, cosø is $\frac{\sqrt{95} }{12}$

Step-by-step explanation:

We are given sinФ = 7/12

We need to find cosФ

The basic trigonometric functions of right triangle are:

$sin\theta=\frac{opposite}{hypotenuse}$

$cos\theta=\frac{adjacent}{hypotenuse}$

We need values of adjacent and hypotenuse to find cosФ

Using Pythagoras theorem we can find the value of adjacent

$(Hypotenuse)^2= (Opposite)^2+(Adjacent)^2$

We have Hypotenuse= 12 and Opposite = 7 (because $sin\theta=\frac{opposite}{hypotenuse}$ and we are given $sin\theta=\frac{7}{12}$

Inserting values and finding adjacent:

$(Hypotenuse)^2= (Opposite)^2+(Adjacent)^2\\(12)^2=(7)^2+(Adjacent)^2\\144=49+(Adjacent)^2\\144-49=(Adjacent)^2\\95=(Adjacent)^2\\\sqrt{(Adjacent)^2} =\sqrt{95}\\Adjacent=\sqrt{95}$