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3 years ago

10

Will someone please explain this to me?

2 answers:

svlad2 [7]3 years ago

6 0

Answer:

hi there!

the correct answer is: 29 degrees

Step-by-step explanation:

if you refer to the picture I have drawn below angle b is supplementary to the the 119 angle (i know I accidentally wrote 118) that means in order to find angle b you need to do 180-119 which equals 61

then since all angles in a triangle add up to 180, you need to perform (180-90-61) which equals 29

Elza [17]3 years ago

4 0

Step-by-step explanation:

m<DAC is the exterior angle of the right angle triangle, where m<ACB and m<ABC are the interior angles of the triangle opposite to the exterior angle

Sum of the opposite interior angles is equal to the exterior angle

m<ACB+ m<ABC=m<DAC

a°+90°= 119°

a°=119-90°

a°=29°

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Find the area under the standard normal probability distribution between the following pairs of z-scores. a. z=0 and z=3.00 e.

prohojiy [21]

Answer:

a. P(0 < z < 3.00) = 0.4987

b. P(0 < z < 1.00) = 0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) = 0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) = 0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d. z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014 and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587 and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 - 0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571 and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 - 0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148 and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 - 0.2148

P(-0.79 < z < 0) = 0.2852

8 0

2 years ago

Find the mean, variance, and standard deviation. If necessary, round your answer to the nearest hundredth.

lora16 [44]

Answer:

Mean = 24

Variance = 107.78

Standard deviation = 10.38

Hope this helps! :)

4 0

2 years ago

Help with steps <br>questions on image

Sveta_85 [38]

Answer:

24

Step-by-step explanation:

all odd numbers possible: 1, 3, 5, 7

__ __ __ __

there are 4 possibilities for the first blank

for the second blank there are 4-1 = 3 possibilities as one of the numbers will have been used

for the third blank there are 4-2 = 2 possibilities as 2 of the numbers have been used

for the last blank there is only 1 possibility

so the number of solutions possible is 4 x 3 x 2 x 1 = 24

7 0

2 years ago

Rohan did a survey in four bird parks and wrote the following observations:

stiks02 [169]

Answer: Park P

Step-by-step explanation:

Since, According to the question,

Number of yellow bird in park P = 33

Total number of the bird in park P = 53

Thus, the percentage of yellow bird in park P = $\frac{33}{53} \times 100$ = 62.264150943% ≈ 62 %

Number of yellow bird in park Q = 20

Total number of the bird in park Q = 48

Thus, the percentage of yellow bird in park P = $\frac{20}{48} \times 100$ =41.666666666% ≈ 42%

Number of yellow bird in park R = 54

Total number of the bird in park R = 90

Thus, the percentage of yellow bird in park R = $\frac{54}{90} \times 100$ = 60 %

Number of yellow bird in park S = 44

Total number of the bird in park S = 83

Thus, the percentage of yellow bird in park P = $\frac{44}{83} \times 100$ =53.012048192 % ≈ 53 %

Since, 62% > 60% > 53% > 42%

Therefore, highest percentage of the yellow bird is 62 %

Which is present in park P.

8 0

2 years ago

Malcom is filling bags with rice. He starts with 5 1/4 lbs. container of rice and fills each bag with 5/8 pound of rice. How man

NeTakaya

He can fill five bags with 2/8 lbs of rice left that is left over a d can not go into a bag .

8 0

2 years ago