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2 answers:
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Answer:
Over the interval [0, 2], the average rate of change of f is greater than that of g. The y-intercept of f is the same as the y-intercept of g.
Step-by-step explanation:
The function i.e mentioned in the question is
Now Placing x = 0, to compute the y-intercept
f(x) y-intercept is -3
As we can see in the given graph the graph of g(x) intersects the y-axis at -3
Therefore the y-intercept of g(x) is -3.
Hence, both functions with respect to the y-intercepts i.e f(x) and g(x) would remain the same
Now At x=2,
So, the value of the function is
The average rate of change of f over the interval [0,2] is
From the mentioned graph as we can see that the graph of g(x) is crossing through the points (0,-3) and (2,12).
The average rate of change of g over the interval [0,2] is
Therefore this is the correct answer but the same is not provided in the given options
Answer:
The largest rectangular space is
Step-by-step explanation:
Given a 20m long wire fence, implies that the perimeter of the fence has been given, because Perimeter can be defined as the length of the boundary of a figure (in this case, a rectangle)
So, from the formula: Perimeter = 2 (L + B) =
We have that L + B =
The possible values of L and B are:
(L, B) = (9, 1), (8, 2), (7, 3) and (6, 4).
The areas of the rectangle that will be formed using these values are respectively; ,
,
and
, the largest area of which is the last which corresponds to the values (6, 4).
The largest rectangular space that the gardener can enclose is therefore