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3 years ago

What is the equation for a circle whose center is at (8,6) and the origin is a point on the circle

Mathematics

1 answer:

blagie [28]3 years ago

3 0

Answer:

hhhh

Step-by-step explanation:

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Can someone pls help me / alguien me puede ayudar

user100 [1]

Answer:

The simplified expression is:

$\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)=0.2y+0.2x-8$

Step-by-step explanation:

Given the expression

$\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{2}{5}y+\frac{1}{5}x-0.2y-6-2$

$\mathrm{Group\:like\:terms}$

$=\frac{2}{5}y-0.2y+\frac{1}{5}x-6-2$

Add similar elements

$=0.2y+\frac{1}{5}x-6-2$

$=0.2y+\frac{x}{5}-6-2$

$=0.2y+\frac{x}{5}-8$

$=0.2y+0.2x-8$

Thus, the simplified expression is:

$\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)=0.2y+0.2x-8$

6 0

3 years ago

one x-intercept for a parabola is at the point (2, 0). use the quadratic formula to find the other x-intercept for the parabola

omeli [17]

Answer:

Step-by-step explanation:

There are 3 ways to find the other x intercept.

1) Polynomial Long Division.

Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.

2) Just solving for x when y = 0, by using the quadratic formula.

$x^2 - 3x + 2 = 0\\x_{12} = \frac{3 \pm \sqrt{9 - 4(1)(2)}}{2} = \frac{3 \pm 1}{2} = 2, 1$ .

So the other x - intercept is at (1, 0)

3) Using Vietta's Theorem regarding the solutions of a quadratic

Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.

$x_1 + x_2 = \frac{-b}{a}$

And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.

$x_1 \cdot x_2 = \frac{c}{a}$