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3 years ago

What is the equation for a circle whose center is at (8,6) and the origin is a point on the circle

Mathematics

1 answer:

blagie [28]3 years ago

3 0

Answer:

hhhh

Step-by-step explanation:

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When 1,250^3/4 is written in simplest radical form, which value remains under the radical?

ddd [48]

Answer:

2 is inside the radical.

Step-by-step explanation:

We have to write the radical expression $1250^{3/4}$ in simplest form

Let us find the factors of 1250

$1250 = 2\times5^4$

Hence, we can rewrite the radical expression as

$(2\times5^4)^{3/4}$

Using the exponent rule $(x^a)^b=x^{ab}$

$(2^{3/4})\times(5^{4\cdot3/4})\\\\=2^{3/4}\times125$

Hence, we have 2 is inside the radical.

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3 years ago

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rjkz [21]

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3 years ago

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Can someone help me pls

antiseptic1488 [7]

CD= 6,9 and M i don't know I hope I helped. Sorry if you get this wrong I tried.

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3 years ago

Write and solve the equation to find the value of x and the missing angle measures.

MrRissso [65]

Answer:

x = 8

The missing measures are 85 degrees

Step-by-step explanation:

Since 9x + 13 and 11x - 3 are on opposite sides, they are equal, so

9x + 13 = 11x - 3

Subtract 13 from both sides:

9x = 11x - 16

Subtract 11x from both sides:

-2x = -16

Divide both sides by -2:

x = 8

The angle measures are

9(8) + 13 = 72 + 13 = 85

11(8) - 3 = 88 - 3 = 85

6 0

3 years ago

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X^2 +x-6=0 How to solve this ?

Svetach [21]

Answer:

x = 2, x = -3

Step-by-step explanation:

We are given the following quadratic equation and we are to solve it for x:

$x ^ 2 + x - 6 = 0$

We need to find such factors of -6 that when added give a result of 1 and when multiplied, give a product of -6.

$x ^ 2 + x - 6 = 0$

$x ^ 2 - 2x + 3x - 6 = 0$

$x ( x - 2 ) + 3 ( x - 2 ) = 0$

$(x-2) = 0, (x+3)=0$

x = 2, x = -3

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3 years ago