Tan(x)= sin(x)/cos(x), therefore, substitute sin(x)/cos(x) in the expression:
=(cos(x)(sin(x)/cos(x))-1)/cos^2(x)
simplify the 2 cos(x):
=(sin(x)-1)/cos^2(x)
Sin^2(x)+ cos^2(x)=1, sin^2(x)-1=- cos^2(x), substitute in the expression:
= -cos^2(x)/cos^2(x)= -1
The awnser is Shari is using the same ratio as Mark's
Answer:
A = 12 ft
Step-by-step explanation:
Perimeter ( of SQUARE) B = 64
then each side = 64/4 = 16
AREA of SQUARE C = 400
side X side = 400
then side = sqrt 400
Now use Pyhtagorean Theorem to find leg of right triangle that is
side A Side B hypotenuse Side C
A^2 + 16^2 = (sqrt 400)^2
A^2 = 400 - 256
A^2 = 144 then A = 12 Ft
Answer:
A ≈ 35.3 units²
Step-by-step explanation:
Calculate the radius CB using Pythagoras' identity in the right triangle.
CB² + AB² = AC²
CB² + 6² = 9²
CB² + 36 = 81 ( subtract 36 from both sides )
CB² = 45 = r²
Then area of quarter circle is
A = 
× πr² = × π × 45 ≈ 35.3
What do u want help with and take it easy btw
