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Drupady [299]
3 years ago
5

Solve m =h-w/8 for the varible h.

Mathematics
1 answer:
anygoal [31]3 years ago
5 0

I think it's   m =h-w/8 Move the sides   H-w/8=M Move -w/8 To right side to get h alone   H=w/8+m

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Write the ratio as a ratio of whole numbers in lowest terms<br><br> $1.00 to $0.80
diamong [38]
5/4
as 1.00/0.80 = 100/80
and then when you simplify it the answer would be 4/5.
6 0
3 years ago
Does anyone know what absolute deviation is..?
Ostrovityanka [42]

Answer:

Mean absolute deviation (MAD) of a data set is the average distance between each data value and the mean. Mean absolute deviation is a way to describe variation in a data set. Mean absolute deviation helps us get a sense of how "spread out" the values in a data set are.

Step-by-step explanation:

To find the mean absolute deviation of the data, start by finding the mean of the data set. Find the sum of the data values, and divide the sum by the number of data values. Find the absolute value of the difference between each data value and the mean: |data value – mean|.

6 0
3 years ago
Read 2 more answers
Could someone help me?<br><br> Why does x^4 * x^-4 = 1?
Alika [10]

Answer:

Step-by-step explanation:

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Does this help?

7 0
3 years ago
Read 2 more answers
Can someone please explain how to do this.
lutik1710 [3]
Set the to equal:

x^2 - 4x+4 = 2x-4
 solve for X

subtract 2x from each side:
x^2 -6x + 4 = -4

subtract 4 from each side:

x^2 -6x = -8

add 8 to both sides:

x^2 -6x +8 = 0

factor the polynomial:

x = 4 and x = 2

using the line equation replace x with 2 and 4 and solve for y

y = 2(2) - 4 = 0
y = 2(4)-4 = 4

so the 2 points the line  crosses the curve is (2,0) and (4,4)

using those 2 points you can calculate the length:
 distance = sqrt((x2-x1)^2 +(y2-y1)^2

distance = sqrt( (4-2)^2 + (4-0)^2)

distance = sqrt (2^2 + 4^2)
 distance = sqrt (4+16)
= sqrt 20 
= 2 sqrt(5)  EXACT LENGTH


4 0
3 years ago
A scientist wants to estimate the number of roads living near a lake.
QveST [7]
90 + 50 = 140
140 - 7 = 133
130 - 140
7 0
3 years ago
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