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Temka [501]
3 years ago
14

Find the coordinates of the points of intersection of the graphs with coordinate axes: y=−1.5x+3

Mathematics
1 answer:
mart [117]3 years ago
4 0

Answer:

(0, 3 ) and (2, 0 )

Step-by-step explanation:

To find the y- intercept let x = 0 in the equation and solve for y

y = - 1.5(0) + 3

y = 3 ← y- intercept ⇒ (0, 3 )

To find the x- intercept let y = 0 in the equation and solve for x

0 = - 1.5x + 3 ( subtract 3 from both sides )

- 3 = - 1.5x ( divide both sides by - 1.5 )

x = 2 ← x- intercept ⇒ (2, 0 )

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Mrs. Nguyen used 1.48 meters of netting to make 4 identical mini hockey goals. How much netting did she use per goal?
snow_tiger [21]

0.37 meters  of netting

<h3>Further explanation</h3>

<u>Given:</u>

Mrs. Nguyen used 1.48 meters of netting to make 4 identical mini hockey goals.  

<u>Question:</u>

How much netting did she use per goal?

<u>The Process:</u>

We will solve the problem of conversion or in other words the ratio or proportion.

Option A: the conversion

Mrs. Nguyen used 1.48 meters of netting to make 4 identical mini hockey goals.  

Then for every 1 goal, she needs 0.37 meters of netting.

Because \boxed{ \ 1 \ goal \times \frac{1.48 \ meters}{4 \ goals} = 0.37 \ meters \ of \ netting.}

Option B: the ratio (or proportion)

In the ratio, we process as follows:

\boxed{ \ 4 \ goals : 1.48 \ meters \ of \ netting \ }

Both are divided by 4.

\boxed{ \ 1 \ goals : 0.37 \ meters \ of \ netting \ }

Thus, she uses 0.37 meters of netting per goal.

Alternative problem

How much netting did she use for 8 goals?

\boxed{ \ 8 \ goal \times \frac{1.48 \ meters}{4 \ goals} = \ ? \ } meters of netting.

We cross out eight and four because they can be divided.

\boxed{ \ 2 \times 1.48 \ meters = 2.96 \ meters \ of \ netting. \ }

She uses 2.96 meters of netting to make 8 identical mini hockey goals.

<h3>Learn more</h3>
  1. About the engine displacement of Kawasaki Ninja brainly.com/question/5009365
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  3. The unit conversion brainly.com/question/5416146  

Keywords: Mrs. Nguyen, 1.48 meters of netting, to make 4 identical mini hockey goals, how much netting, she uses per goal, conversion, the ratio, proportion

8 0
4 years ago
The rate of change is<br><br> A. -4<br> B. -1<br> C. 1<br> D. 4
babymother [125]
The rate of change is 4 so your answer would be D. 4
3 0
3 years ago
Gianni was thinking about paying his mother back in less than 100 weeks if he pays his mother $20 a week how many week will it t
weeeeeb [17]
What is the total amount of money he owes back?
6 0
4 years ago
Read 2 more answers
How many pounds of a 23% zinc alloy must be mixed with a 42% zinc alloy to make 516 pounds of a 37.25% zinc alloy?
nydimaria [60]

Answer:

(A)129 Pounds

Step-by-step explanation:

Let x be the number of 23% zink alloy

Therefore:

Since the total result is 516 pounds

The number of pounds of 42% zink alloy =516-x pounds

We then have the resulting equation:

0.23x+0.42(516-x)=0.3725*516

0.23x+216.72-0.42x=192.21

Colect like terms

0.23x-0.42x=192.21-216.72

-0.19x=-24.51

Divide both sides by 129

x=129 pounds

Therefore, the number of pounds of 23% zink alloy that must be mixed is 129 pounds.

6 0
3 years ago
A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a
tatuchka [14]

Answer:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

df=n-1=15-1=14  

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

\bar X=42.6 represent the average nicotine content

s=3.7 represent the sample standard deviation

n=15 sample size  

\mu_o =40 represent the value to check

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

The statistic for this case would be:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replcing we got:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

The degrees of freedom are:

df=n-1=15-1=14  

The p value would be:

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

6 0
3 years ago
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