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scoundrel [369]
3 years ago
9

Is the sky a solid liquid or gas

Chemistry
2 answers:
hram777 [196]3 years ago
8 0

Answer:

gas

Explanation:

The sky is not a solid body, nor does it have all of the same the physical properties of a solid body. In terms of its behavior, physically a gas is much closer to a liquid than a solid. If you drop the temperature of the atmosphere quick enough and low enough it can become a solid.

s2008m [1.1K]3 years ago
6 0
Gas.
The sky is not solid, not liquid but of gas. It is also called the atmosphere, one of the important spheres on earth that influences the climate –temperature, humidity, precipitation, atmospheric pressure, and the biotic community as a whole. The atmosphere or the sky is composed of many layers and is responsible to protecting the living organisms of the earth against the deadly ultraviolet rays and other strong radiation coming from the sun.



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The data showed that recently the alligator population has decreased. How could the decrease in the alligator
Marina CMI [18]

Answer:

Since the alligator population decreased, this means there are less predators for the gar. Less predators for the gar mean the gar population will increase.  More gar also means more competition for the diving duck in terms of animals that eat crabs, and thus the diving duck population will also decrease.

Explanation:

Hope this helped <3

4 0
3 years ago
If you lived in Alaska, which of the following natural gases could you keep in an outdoor storage tank in winter: a. Methane (CH
wariber [46]

Answer:

Methane

Explanation:

The gas that you could keep in an outdoor storage tank in winter in Alaska is Methane.

The reason is the extreme low temperature during the winter. The boiling point of butane is 44 ºF ( -1ºC) and that of propane is a higher -43.6 º F but still within the range of average minimum winter temperature in Alaska (-50 ªF). Therefore we will have condensation in the tanks and not enough gas pressure.

Methane having  a boling point  of  -259 ºF will not condense at the low wintertime temperatures in Alaska.

3 0
3 years ago
Read 2 more answers
The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water.
avanturin [10]

a. 0.137

b. 0.0274

c. 1.5892 g

d. 0.1781

e. 5.6992 g

<h3>Further explanation</h3>

Given

Reaction

2 C4H10 + 13O2 -------> 8CO2 + 10H2O

2.46 g of water

Required

moles and mass

Solution

a. moles of water :

2.46 g : 18 g/mol = 0.137

b. moles of butane :

= 2/10 x mol water

= 2/10 x 0.137

= 0.0274

c. mass of butane :

= 0.0274 x 58 g/mol

= 1.5892 g

d. moles of oxygen :

= 13/2 x mol butane

= 13/2 x 0.0274

= 0.1781

e. mass of oxygen :

= 0.1781 x 32 g/mol

= 5.6992 g

6 0
3 years ago
Energy Levels of an atom. Explain.
Flura [38]
Energy levels inside an  are the specific  that electrons can have when occupying specific orbitals. Electrons can be excited to higher by absorbing from the surroundings. Light is emitted when an electron relaxes from a high  state to a lower one.

7 0
3 years ago
A 100.0 mL solution containing 0.923 gof maleic acid (MW=116.072 g/mol) is titrated with 0.265 M KOH. Calculate the pH of the so
Vlad1618 [11]

Answer:

pH = 9,57

[M²⁻] = 7,948x10⁻²M

[HM⁻] = 4x10⁻⁵M

[H₂M] = 0M

Explanation:

The moles of maleic acid presents in the solution are:

0,923g×\frac{1mol}{116,072g}=7,952x10⁻³moles of H₂M

60,0mL of 0,265M KOH are:

0,0600L×\frac{0,265mol}{1L}=0,0159 moles of KOH

The reactions of maleic acid (H₂M) and then with HM⁻ are:

H₂M + KOH → HM⁻ + H₂O + K⁺ (1)

HM⁻ + KOH → M²⁻ + H₂O + K⁺ (2)

For a complete transformation of H₂M in HM⁻ there are necessaries 7,952x10⁻³moles of KOH. As the moles of KOH are 0,0159 moles, the restant moles are:

0,0159 - 7,952x10⁻³ = <em>7,948x10⁻³ moles of KOH</em>

By (2), the moles produced of M²⁻ are the same as moles of KOH, <em>7,948x10⁻³  moles, </em>and moles of HM⁻ are:

7,952x10⁻³ -<em> </em>7,948x10⁻³ <em> = 4x10⁻⁶ moles of HM⁻</em>

Using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [M²⁻] /[HM⁻]

pH = 6,27 + log₁₀ <em>7,948x10⁻³ / 4x10⁻⁶</em>

pH = 9,57

The moles of M²⁻ are 7,948x10⁻³  and volume of the solution is 0,1000L,

[M²⁻] = 7,948x10⁻²M

Moles of HM⁻ are 4x10⁻⁶:

[HM⁻] = 4x10⁻⁵M

And there is not H₂M:

[H₂M] = 0M

I hope it helps!

8 0
3 years ago
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