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neonofarm [45]
3 years ago
10

Help with this question for chemistry!!

Chemistry
1 answer:
wel3 years ago
7 0
Emperic formula is SO subscript 2. Molecular formula would be SO subscript 2 multiply 1 so it's the same answer.
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2CO + O2 --> 2CO2
GREYUIT [131]

Answer:

10 L of CO₂.

Explanation:

The balanced equation for the reaction is given below:

2CO + O₂ —> 2CO₂

From the balanced equation above,

2 L of CO reacted to produce 2 L of CO₂.

Finally, we shall determine the volume of CO₂ produced by the reaction of 10 L CO. This can be obtained as follow:

From the balanced equation above,

2 L of CO reacted to produce 2 L of CO₂.

Therefore, 10 L of CO will also react to produce 10 L of CO₂.

Thus, 10 L of CO₂ were obtained from the reaction.

3 0
3 years ago
If I leave 750 mL of 0.75 M sodium chloride solution uncovered on a windowsill and 150 mL of the solvent evaporates, what will t
maks197457 [2]

the answer to your question is

M1V1=M2V2

V2=750-150=600 ml

0.75M*750 ml = M2*600

M2=0.75*750/600 ≈ 9.38 M


3 0
3 years ago
If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.
kicyunya [14]
Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

CH_{3}COOH \ \textless \ ---\ \textgreater \   H^{+} + CH_{3}COO^{-}

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> [H^{+}]  = 10^{-2.88} =  0.001 moldm^{-3}

The change in Concentration Δ [CH_{3}COOH]= 0.001 moldm^{-3}


                                  CH3COOH          H+           CH3COOH    
Initial  moldm^{-3}                      x           0                     0
                                                                                                                       
Change moldm^{-3}        -0.001            +0.001           +0.001
                                                                                                       
Equilibrium moldm^{-3}      x- 0.001      0.001             0.001
                                                                              

Since the k_{a} value is so small, the assumption 
[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium} can be made.

k_{a} = [tex]= 1.8*10^{-5}  =  \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} =  \frac{0.001^{2}}{x}

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

         2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps! 



8 0
3 years ago
Faraday's law calculates how many amperes are generated. True or false?
Assoli18 [71]
Hmm well thinking of how amperes are generated it should be true
5 0
3 years ago
Read 2 more answers
When you drop an object, slows it down
sashaice [31]
Gravity slows it down dramatically so that is why it slows down 
7 0
3 years ago
Read 2 more answers
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