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kramer
3 years ago
11

Write the formula for the conjugate acid of each of the following bases. 1. NH₃

Chemistry
1 answer:
tino4ka555 [31]3 years ago
8 0

Answer:

According to Bronsted-Lowry theory, an<u> acid</u> is any species that can<em> donate</em> H+ (proton), while a<u> base</u> is any species that can<em> accept</em> a H+ ion.

  1. NH_{3}  

                          NH_{3}(aq) + H_{2}O(aq) → NH_{4}^{+}(aq)+ OH^{-}(aq)

NH_{4}^{+} is the conjugate acid of NH_{3}

      2. ClO_{3}^{-}

                           ClO_{3}^{-}(aq) + H_{2}O(aq) → HClO_{3}(aq) + OH^{-}(aq)

HClO_{3} is the conjugate acid of ClO_{3}^{-}

       3. SO_{4}^{2-}

                             SO_{4}^{2-}(aq) + H_{2}O(aq) → HSO_{4}^{-}(aq) + OH^{-}(aq)

HSO_{4}^{-} is the conjugate acid of  SO_{4}^{2-}  

         4. OH^{-}

                              OH^{-}(aq) + H^{+}(aq) → H_{2}O(aq)

H_{2}O is the conjugate acid of OH^{-}

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Chloroform flows through a 4.26 inch inside-diameter pipe at the rate of 3.60 gallons per minute. What is the average velocity o
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Explanation:

The relation between flow and velocity of a fluid is given by:

Q=Av

where:

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  • A, cross section of the pipe [ft2]
  • v, velocity of the fluid [ft/s]

1)

To convert our data to appropiate units, we use the following convertion factors:

1 ft=12 inches

1 ft3=7,48 gallons

1 minute=60 seconds

So,

Q=\frac{3,60 gallons}{1 min}*\frac{1min}{60 s}*\frac{1ft3}{7,48gallons}=0,00802 \frac{ft3}{s}

As the pipe has a circular section, we use A=πd^2/4:

d=4,26 inch *\frac{1ft}{12 inch}=0,355ft\\  A=\pi \frac{0,355^{2} }{4}=0,0989ft2

Finally:

Q=vA......................v=Q/A

v=\frac{0,00802ft^{3} /s}{0,0989ft^{2} }=0,081ft/s

2)

The following formula is used to calculate the specific gravity of a material:

SG = ρ / ρW  

where:

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then:

ρ = SG*ρW   = 1,49* 62,4 lb/ft3 = 93 lb/ft3

To calculate the mass flow, we just use the density of the chloroform in lb/ft3 to relate mass and volume:

0,00802 \frac{ft3}{s}*\frac{93lb}{1ft3}=0,746lb/s

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