How many grams are in CO2?

Which statement BEST explains whether or not matter is conserved in this chemical reaction?

timurjin [86]

Answer:

D:Matter is not being conserved because there are 11 units in the reactants, one C8H8 and 10 O2, and 12 units in the products, eight CO2 and four H2O, so there is also more mass in the products that in the reactants.

Explanation:

searched up

4 0

2 years ago

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If the aluminum block is initially at 25 ∘C, what is the final temperature of the block after the evaporation of the alcohol? As

skad [1K]

Explanation:

The given data is as follows.

Heat of vaporization ( $\Delta H_{vap}$ ) = 45.4 kJ/mol

Specific heat ( $C_{p}$ ) = 0.903 $j/g^{o}C$

Let us assume the alcohol given is $C_{3}H_{8}O$ and its mass is 1.12 g. Also, mass of aluminium block is 73.0 g.

First, calculate the moles of alcohol ( $C_{3}H_{8}O$ ) as follows.

No. of moles alcohol = $\frac{mass}{\text{molar mass}}$

= $\frac{1.12 g}{60.1 g/mol}$

= 0.0186 mol

So, heat absorbed by the alcohol ( $q_{alcohol}$ ) = heat lost by aluminium ( $q_{aluminium}$ )

$n \times \Delta H_{vap}$ = $-m \times C_{p} \times \Delta T$

$0.0186 mol \times 45.4 kJ/mol = - 73.0 g \times 0.903 J/g^{o}C \times (T_{f} - 25^{o}C)$

12.71 = $- (T_{f} - 25^{o}C)$

$T_{f} = 12.3^{o}C$

Thus, we can conclude that the final temperature of the block is 12.3^{o}C[/tex].

7 0

3 years ago

One solution has a formula C (n) H (2n) O (n) If this material weighs 288 grams, dissolves in weight 90 grams, the solution will

saw5 [17]

Explanation:

The given data is as follows.

Boiling point of water ( $T^{o}_{b}) = 100^{o}C$ = (100 + 273) K = 323 K,

Boiling point of solution ( $T_{b}) = 101.24^{o}C$ = (101.24 + 273) K = 374.24 K

Hence, change in temperature will be calculated as follows.

$\Delta T_{b} = (T_{b} - T^{o}_{b})$

= 374.24 K - 323 K

= 1.24 K

As molality is defined as the moles of solute present in kg of solvent.

Molality = $\frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}$

Let molar mass of the solute is x grams.

Therefore, Molality = $\frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}$

m = $\frac{288 g \times 1000}{x g \times 90}$

= $\frac{3200}{x}$

As, $\Delta T_{b} = k_{b} \times molality$

$1.24 = 0.512 ^{o}C/m \times \frac{3200}{x}$

x = $\frac{0.512 ^{o}C/m \times 3200}{1.24}$

= 1321.29 g

This means that the molar mass of the given compound is 1321.29 g.

It is given that molecular formula is $C_{n}H_{2n}O_{n}$ .

As, its empirical formula is $CH_{2}O$ and mass is 30 g/mol. Hence, calculate the value of n as follows.

n = $\frac{\text{Molecular mass}}{\text{Empirical mass}}$

= $\frac{1321.29 g}{30 g/mol}$

= 44 mol

Thus, we can conclude that the formula of given material is $C_{44}H_{88}O_{44}$ .

4 0

3 years ago

What is biomolecules

sattari [20]

Biomolecules also called biological molecules, any of numerous substance that are produced by cells and living organisms

4 0

2 years ago

Obtain a box of breakfast cereal and read the list of ingredients. What are four chemicals from the list? a. monoglycerides b. c

GREYUIT [131]

Answer:

B. cocamide DEA

C. folic acid

D. iron

G. lauryl glucoside

5 0

3 years ago