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There are 1952.31g of nickel can be converted to the carbonyl with 3.55 m³ of CO at 100.7 kPa.
Given data
The reaction can be written as:
Ni+4CO ⟶
V(CO)=3.55
T=50°C=323.5K
p=100700Pa
Now, use the formula:
pV=nR*T
Where, P is pressure, V is volume and T is temperature. n=p∗V / R∗T
n=100700∗3.55 / 8.314∗323.15
It is known that,
n(CO)=133.059mol
n(Ni)=n(CO)/4=33.26mol
Mass can be determined by the formula:
Mole = mass / molar mass
Now, put the value of given data in above formula:
m(Ni)=nAr=33.26mol/58.69g/mol
m(Ni)=1952.31g
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