ANSWER: Increase
why? Because the number of C atoms in homologous series increases gradually.
The laws of the electrostatics were developed by Coulomb and are further detailed or subdivided into two as follows:
(1) The first one talks about the similarities in the charges of the particles and what happens to them. This states that like charges repel.
(2) The second one quantifies the field between two particles with equation showing that field is directly proportional to the masses and inversely to the square of the distance between them.
In this item, we can then say that the protons (having the same charges) will have to repel from each other in accordance to statement 1 of the law.
Answer:
NH3 + HCl → NH4Cl: this equation is balanced as it has one nitrogen atom, four hydrogen atoms and one chlorine atom at each side of the equation.
Explanation:
Hello there!
In this case, according to the law of conservation of mass, we need to have the same number of atoms of each element at both sides of the equation; therefore we analyze each reaction:
NaOH + H2CO3 → Na2CO3 + H2O
: three hydrogens at the left and two at the right, so this is not balanced.
N2 + H2 → 2NH3: two hydrogens at the left and six at the right, so this is not balanced.
NH3 + HCl → NH4Cl: this equation is balanced as it has one nitrogen atom, four hydrogen atoms and one chlorine atom at each side of the equation.
AlCl3 + Li → Al + LiCl: three chlorines at the left and one of the right, so this is not balanced.
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J.J. Thomson discovered the electron by noticing that a beam of particles could be influenced by an electric or magnetic force and is denoted as option B.
<h3>What is an Electron?</h3>
This is referred to a subatomic particle which has a negative charge present and is involved in chemical reactions.
J.J. Thomson noticed that cathode rays were negatively charged due to deflection by magnetic and electric forces which signifies the presence of a negative particle.
Read more about J.J. Thomson here brainly.com/question/15361325
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Answer:
There are 8.55ₓ10²⁵ atoms of P, in 7.1 moles of Cu₃(PO₄)₂
Explanation:
Copper (II) ⇒ Cu²⁺
PO₄⁻³ → phosphate
3Cu²⁺ + 2PO₄⁻³ → Cu₃(PO₄)₂
1 mol of copper (II) phosphate has 2 mol of P, 8 moles of O and 3 moles of Cu.
Then, 7.10 moles of salt has (7.1 .2) = 14.2 moles of P
In 1 mol we find, NA atoms (6.02ₓ10²³)
In 14.2 moles we would find (14.2 .NA) = 8.55ₓ10²⁵ atoms
