Question

Find the missing term (x^12)^5 x (x^-2)^9 x what =(x^40)^5

Answer 1

Answer:

The missing term is x^158

Step-by-step explanation:

Let A denote the missing term.

$(x^{12})^5 \cdot (x^{-2})^9 \cdot A =(x^{40})^5\\x^{60}\cdot x^{-18}\cdot A = x^{200}\\x^{42}\cdot A = x^{200}\\A = x^{200}\cdot x^{-42}=x^{158}$

Answer 2

Answer:

$x^{158}$

Step-by-step explanation:

We are given,

$(x^{12} )^{5} \times (x^{-2} )^{9} \times y = (x^{40} )^{5}$.

It is required to find the value of y.

Now, on simplifying above equation, we get,

$x^{60} \times x^{-18} \times y = x^{200}$

i.e. $x^{42} \times y = x^{200}$

i.e. $y = x^{200} \times x^{-42}$

i.e. $y = x^{158}$

Hence, the missing term is $x^{158}$.