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3 years ago

Given the following sets.

Mathematics

1 answer:

asambeis [7]3 years ago

4 0

A = {0, 1, 2, 3}

C = {0, a, 2, b}

A ∩ C = {0, 2} → E)

A set of the same elements from the set A and the set C.

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Camille bought 3 pounds of nuts for $10.35 what is the unit price per pound

amid [387]

$10.35 \div 3 = 3.45$
the unit price per pound is $3.45

5 0

3 years ago

Implicit differentiation in terms of x and y

Volgvan

For implicit differentiation, you are using the chain rule
$f'(x) = g'(u(x))* \frac{du}{dx}$
Except u(x) = y, So after every "y" term is differentiated it will be multiplied by dy/dx.

17) $y^3 +4 = 3x \\ 3y^2 \frac{dy}{dx} +0 = 3$
Then you solve for dy/dx as if its a variable.
$\frac{dy}{dx} = \frac{3}{3y^2} = \frac{1}{y^2}$

18) Here lets review product rule:
$(fg)' = f'g + fg'$
Take derivative of each term
$2x^2 = -3y^3 +3x^2y^3 \\ 4x = -9y^2 \frac{dy}{dx} + (6x)(y^3) + (3x^2)(3y^2 \frac{dy}{dx}) \\ 4x = -9y^2 \frac{dy}{dx} +6xy^3 +9x^2y^2 \frac{dy}{dx}$
Solve for dy/dx using factoring:
$4x - 6xy^3 = -9y^2 \frac{dy}{dx}+9x^2 y^2 \frac{dy}{dx} \\ 4x - 6xy^3 = \frac{dy}{dx}(-9y^2 +9x^2 y^2) \\ \frac{dy}{dx} = \frac{4x - 6xy^3}{-9y^2 +9x^2 y^2}$

8 0

3 years ago

Supervisor a earns a flat rate of $25 per hour, while supervisor b earns $20 per hour for the first 30 hours and then 50% more f

jek_recluse [69]

A: 25h
b:20h+30(h-30)
25h=20h+30(h-30)
5h=30h-30^2
-25h=-30^2
25h=30^2
h=900/25

8 0

2 years ago

Read 2 more answers

48 girls, 41 boys, and 5 teachers sat in the gym. Write the ratio of girls to boys in three ways.

Anika [276]

Answer:

Step-by-step explanation:

The answer is D because the question is asking for girls to boys. So anything that has 5 in it is wrong because it isn't asking for teachers, which eliminates A. So since it is asking girls to boys the number order has to be 48 then 41 because it is asking for girls first then to boys. So that makes B wrong. When it comes to the fraction part of the ratio the first number it is asking for (which is girls) always goes on top. So that eliminates C which leaves only answer to be D.

7 0

2 years ago

A probability experiment is conducted in which the sample space of the experiment is Sequals=StartSet 9 comma 10 comma 11 comma

White raven [17]

Answer:

From both approaches P(F or G)=0.667

Step-by-step explanation:

P(F or G)=?

F={9, 10, 11, 12, 13}

G={13,14,15,16}

Finding P(F or G) by counting outcomes in F or G

F or G={9, 10, 11, 12, 13}or {13,14,15,16}

F or G={9, 10, 11, 12,13,14,15,16}

number of outcomes in F or G=n(F or G)=8

S={9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}

number of outcomes in S=n(S)=12

P(F or G)=n(F or G)/n(S)

P(F or G)=8/12

P(F or G)=0.667

Finding P(F or G) by addition rule

P(F or G)=P(F)+P(G)-P(F and G)

F={9, 10, 11, 12, 13}

number of outcomes in F=n(F)=5

P(F)=n(F)/n(S)

P(F)=5/12

P(F)=0.417

G={13,14,15,16}

number of outcomes in G=n(G)=4

P(G)=n(G)/n(S)

P(G)=4/12

P(G)=0.333

F and G={9, 10, 11, 12, 13}and {13,14,15,16}

F and G={13}

number of outcomes in F and G=n(F and G)=1

P(F and G)=n(F and G)/n(S)

P(F and G)=1/12

P(F and G)=0.083

P(F or G)=P(F)+P(G)-P(F and G)

P(F or G)=0.417+0.333-0.083

P(F or G)=0.667

8 0

2 years ago

Read 2 more answers