Write the ratio as a fraction in simplest form. 4 : 40

2 answers:

7 0

The answer is: " 1:10 " .
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Note: 4: 40 = 4/40 = (4÷4)/(40÷4) = 1/10 ; or, 1:10 .
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Alenkinab [10]4 years ago

3 0

The Answer To This Would 1 : 10 Because You Have To Divide Both By 4 So 4 Divided By 4 Gives You 1 And 40 Divided By 4 Gives You 10

~ Hope This Helps :)

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in a survey of 400 people ,160 people said they would rather have a cat instead of a dog .what percent of the people said they w

Leya [2.2K]

Hi,

For this question, your answer would 40%.

All you had to was divide 160 by 400.

7 0

3 years ago

The mean weight of boxes shipped by a company is 12 lbs., with a standard deviation of 4 lbs. Assume weight of boxes follows Nor

777dan777 [17]

Answer:

0.89% probability that a palette of 10 boxes will exceed that limit (150 lbs.)

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 12, \sigma = 4, n = 10, s = \frac{4}{\sqrt{10}} = 1.2649$

1. What’s the probability that a palette of 10 boxes will exceed that limit (150 lbs.)? a. HINT: Prob (total weight of a sample of 10 boxes >150 lbs.) = Prob (the sample mean weight ( y hat ) > 15 lbs.)

This is 1 subtracted by the pvalue of Z when X = 15. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$