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guapka [62]
3 years ago
7

3. Which expression is equivalent to 1+2(x-1)

Mathematics
1 answer:
padilas [110]3 years ago
8 0

Answer:

<em>2x - 1</em>

Step-by-step explanation:

<u>Equivalent Algebraic Expressions </u>

One algebraic expression can be written in several ways by applying known rules and theorems that modify expressions without changing its final value.

The expression:

1 + 2(x - 1)

Can be modified by applying the following operations:

Multiplying the constant by the contents in parentheses:

1 + 2x - 2

Collecting like terms:

-1 + 2x

Or, equivalently:

2x - 1

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3 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
Are these equations equivalent?
Tpy6a [65]

Answer:

Yes, 2x=4 is 2 simply by dividing, and 4x+5=13 is 2 as well, because 5-13 is 8 and 8 divided by 4 is 2

4 0
3 years ago
Read 2 more answers
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