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Gelneren [198K]
2 years ago
5

Roblem #7

Mathematics
1 answer:
gtnhenbr [62]2 years ago
3 0

Answer:

no solution.

Step-by-step explanation:

1) in order to explain, the given system should be resolved:
\left \{ {{2y=6x+4} \atop {y=3x-4}} \right. \ < = > \ \left \{ {{y=3x+2} \atop {y=3x-4}} \right.

2) the both equations have the same slope (it is 3), it means the given lines are parallel, then no solution.

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a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
I'LL WON'T BE OFFEND IF U DON'T HELP ME WITH THIS
Evgesh-ka [11]

The average is found by adding the numbers and dividing by 2.

Since the average is 17, the total of the two numbers must equal 17 x 2 = 34.


One number is given as 11, so subtract 11 from 34:

34 - 11 = 23

The other number is 23.

Too check: add 11 and 23 and then divide by 2:

11 + 23 = 34

34/2 = 17.

5 0
3 years ago
Read 2 more answers
Which equation could be used to find the length of the hypotenuse?
inysia [295]

The first option .

.................................

8 0
3 years ago
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Line BD is tangent to circle O at C, Arch AEC = 299, and ACE = 93. Find Angle DCE.
VladimirAG [237]
In triangle ACE,
we know C=93,E can be calulated by using arch angle AEC...what ever that is....,using this we get  A=180-(E+93)

So, by alternate segment theorem, DCE= A.

thats all i can say.
7 0
3 years ago
I need helps pls :)
nadya68 [22]
In regular polygons, if the number of sides, n, is odd, the lines of symmetry will pass through a vertex and the half of the opposite side.
Step-by-step explanation:
This is equivalent to say that a perpendicular bisector of a side of the regular polygon bisects the angle of the opposite vertex to the side, and divide the polygon into two symmetrical parts.
4 0
2 years ago
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