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3 years ago

(4x2 - 10x -24) (2x + 3)

Mathematics

1 answer:

jeyben [28]3 years ago

3 0

Answer:

Apply BODMAS

Step-by-step explanation:

PLEASE FIND THE PICTURE BELLOW

SOLUTION STEPS

(4⋅2−10x−24)(2x+3)

Multiply 4 and 2 to get 8.

(8−10x−24)(2x+3)

Subtract 24 from 8 to get −16.

(−16−10x)(2x+3)

Apply the distributive property by multiplying each term of −16−10x by each term of 2x+3.

−32x−48−20x

−30x

Combine −32x and −30x to get −62x.

−62x−48−20x

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3 years ago

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4 years ago

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3 years ago

The parallelogram ABCD below, line AC is a diagonal, the measure of angle ABC is 40, and the measure of angle ACD is 57. What is

Strike441 [17]

Answer:

Using properties of parallelogram and angle sum property of a triangle in the figure as shown below in the attachment

In parallelogram ABCD, AC is a diagonal.

Given: $\angle ABC = 40^{\circ}$ and $\angle ACD= 57^{\circ}$

As, we know that opposite angles in parallelogram are equal.

therefore,

$\angle ABC =\angle ADC= 40^{\circ}$

Now, in ΔADC

Sum of the measures of angles in a triangle is 180 degree.

$\angle ACD+ \angle ADC+\angle DAC =180^{\circ}$

Substituting the values of $\angle ADC= 40^{\circ}$ and $\angle ACD= 57^{\circ}$ we have;

$57^{\circ}+40^{\circ}+\angle DAC =180^{\circ}$

$97^{\circ}+\angle DAC =180^{\circ}$

Subtract $97^{\circ}$ from both sides we get

$\angle DAC =180 -97 =83^{\circ}$

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3 years ago