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Alex
3 years ago
14

Croatia won 10 medals at the 2016 Summer Olympics. 5 were Gold, 3 were Silver and the rest were Bronze. What's the ratio of Gold

:Bronze?
Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0

Answer:

5:2

Step-by-step explanation:

First, we need to find how many bronze medals were won.

We know they earned a total of 10, and the gold, silver and bronze medals added must equal 10.

gold+silver+bronze=10

We also know they won 5 gold and 3 silver

5+3+bronze=10

8+bronze=10

Subtract 8 from both sides

bronze=2

So, Croatia won 5 gold, 3 silver, 2 bronze

The ratio of gold:bronze

We know they won 5 gold and 2 bronze, so plug those into the ratio

gold: bronze

5:2

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Given a function of the following type:

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In this case, we have f(t)= -tan0.4t. Then:

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2 years ago
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Suppose we want to choose 5 colors, without replacement, from 8 distinct colors.1. If the order is relevant, how many can be don
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(1) From the information given, if we want to choose 5 colors from 8 distinct colors and the order in which the selection is made is relevant, then what we have is a permutation.

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This formula means we need to select/arrange r items out of a total of n items and the anwer derived would be the total number of arrangements possible.

Therefore, we would have;

\begin{gathered} nP_r\Rightarrow_8P_5 \\ _8P_5=\frac{8!}{(8-5)!}\Rightarrow\frac{8!}{3!} \\ _8P_5=\frac{8\times7\times6\times\ldots1}{3\times2\times1}\Rightarrow\frac{40320}{6} \\ _8P_5=6720 \end{gathered}

Therefore, if the order is relevant, this selection can be done in 6,720 ways.

(2) If the order is NOT relevant, then what we need to calculate is a combination and the formula is;

_nC_r=\frac{n!}{(n-r)!r!}

The formula can now be applied as follows;

\begin{gathered} _nC_r\Rightarrow_8C_5 \\ _8C_5=\frac{8!}{(8-5)!\times5!} \\ _8C_5=\frac{8!}{3!\times5!}\Rightarrow\frac{8\times7\times6\times\ldots1}{(3\times2\times1)\times(5\times4\times\ldots1)} \\ _8C_5=\frac{40320}{6\times120} \\ _8C_5=56 \end{gathered}

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