Answer:
about 0.177 mg/mL
Step-by-step explanation:
The maximum is found where the derivative of C(t) is zero.
dC/dt = 1.35e^(-2.802t) -(1.35t)2.802e^(-2.802t) = 0
Solving for t gives ...
t = 1/2.802
So, the maximum C(t) is ...
C(1/2.802) = 1.35/2.802e^(-1) ≈ 0.177 . . . . . mg/mL
The maximum average BAC during the first 6 hours is about 0.177 mg/mL.
_____
The maximum occurs about 21 minutes 25 seconds after consumption.
1) you have to find the difference between pipe A and pipe B, which is 6.40.
23.55-17.15=6.40
2) after finding the difference. You will take that difference and put it out of 23.55 and multiply by 100 to get your percentage. As so:
(6.40/23.55)(100)= 27.176% which rounds to 27% as a whole number.
Your answer is 27%. Hope that helps!
X=1, y=4
Substitute 4x in for y in the second equation and you get 5x=5. Divide out 5 and you get x=1. Then, you can plug 1 in for x into either equation and solve for y.
Answer:
no association because there is no specific pattern
52mph, depending what unit you need the answer in you may have to use conversions
