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shtirl [24]
3 years ago
9

Convert the rational expression to radical form m^2/3

Mathematics
1 answer:
Igoryamba3 years ago
6 0

\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ m^{\frac{2}{3}}\implies \sqrt[3]{m^2}

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taurus [48]

C is the answer to your question

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3 years ago
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I need help 15 points scientific notation
Radda [10]

for number 19, figure out the exponents then multiply.

for scientific notaintion you figure out how many numbers are behind the decimal , then do that number as an exponient to 10 then multiply by that number. i hope i made a bit of sense. if not look at kahn academy for help !


8 0
4 years ago
Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
morpeh [17]

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0
4 years ago
Mr wells drew a plan for a rectangle dog run three of the vertices are (2 1/3, 7 1/2), (12, 7 1/2), and (12, 1) what are the coo
melisa1 [442]

Answer:

Step-by-step explanation:

let 4th fourth vertex be D (x,y)

A(2 1/3,7 1/2),B(12, 7 1/2),C(12,1)

or A(7/3,15/2),B(12,15/2),C(12,1)

Mid-point of diagonal AC is  P((7/3+12)/2,(15/2+1))

Mid -point of diagonal BD is P((12+x)/2,(15/2+y)/2)

(Because mid -point of diagonal is same.)

(12+x)/2=(7/3+12)/2

12+x=7/3+12

x=7/3

(15/2+1)/2=(15/2+y)/2

15/2+1=15/2+y

y=1

so fourth vertex is (7/3,1)

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denis-greek [22]
10minutes= 10/60 hours
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=3/ (1/6)
= 18 km/h
5 0
4 years ago
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