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const2013 [10]
3 years ago
9

A garment shop earns a profit of ₹100 on every shirt and loss ₹50 on every sale of half pant. (1) The shop sells in a month 50 h

alf shirt and 150 half pants. What is the profit or loss. (2) If the shop owner sells 50 half pants in a month, how many shirts he has to sell to earn a profit of ₹5000 per month. (please explain the 2 Question answer carefully)​
Mathematics
1 answer:
Illusion [34]3 years ago
8 0

Answer:

a. -₹2,500

b. 75 shirts

Step-by-step explanation:

The computation is shown below:

a. The profit or loss is

=  ₹100 × 50 shirts +  -₹50 × 150 half pants

=  ₹5,000 -  ₹7,500

=  -₹2,500

b. The number of shirts for earning a profit of  ₹5,000 per month is

Let us assume the money needed is x

So, the equation would be

- ₹2,500 + x =  ₹5,000

x =  ₹5,000 +  ₹2,500

=  ₹7,500

Now the number of shirts required is

=  ₹7,500 ÷ 100 shirts

=  75 shirts

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Answer:

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This means, for instance, to see if it can be simplified at all.

Multiply x and 5

Multiply x and 1

The x just gets copied along.

The answer is x

x

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5*x+2 evaluates to 5x+2

So, all-in-all, the left hand side of your inequality can be written as: 5x+2

Now, let's work on the right hand side of your inequality, the 32

The right hand side of your inequality can be written as: 32

So with these (any) simplifications, the inequality we'll set out to solve is:

5x+2 ‹ 32

Move the 2 to the right hand side by subtracting 2 from both sides, like this:

From the left hand side:

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The answer is 30

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To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

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The last step is to divide both sides of the inequality by 5 like this:

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