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Mekhanik [1.2K]
3 years ago
13

How to do this??????????

Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0
The answer should be 5 idk for sure though
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Solve the inequality. Help appreciated
Ivan

Answer:

See below.

Step-by-step explanation:

6x-2≤9

   +2 +2

6x≤11

/6   /6

x≤11/6

4+3x>15

-4      -4

3x>11

/3   /3

x>11/3

-hope it helps

6 0
2 years ago
What’s the answer?????
S_A_V [24]
30 units^3 (just count the blocks inside) :)
3 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST AND 30 POINTS!!!!!
garik1379 [7]

Answer:

Step-by-step explanation:

If the price is supposed to be dropping with each year, maybe your year/price chart would reflect that. Seems to me that the price rose between 2015 and 2016 and even by 2017 the value was still higher than it was in 2015.

I have no way of knowing how to fix this.

Let's ASSUME that the 2015 price was $71,445 and that the 2016 and 2017 prices are valid.

the decrease between 2015 and 2016 is (71445 - 68640) / 71445 = 0.03926

or 3.926%

the decrease between 2016 and 2017 is (68640 - 65945)/68640 = 0.03926

or 3.926%

so the price each year after new is

p = 71445(1 - 0.03926)ⁿ

or

71445(0.96074)ⁿ

where n is the number of years.

To get the monthly version, we divide the decrease by 12

p = 71445(1 - 0.03926/12)ˣ

or

p = 71445(1 - 0.00327)ˣ

or

p = 71445(0.99673)ˣ

where x is the number of months since new.

This may not be your exact answer, but the same method can be used if you get real numbers.

8 0
2 years ago
When 3a + 7b > 2b -8b is solve for a the result is
Travka [436]

Answer:

3a+7b>2b-8b

3a>2b-8b-7b

3a>2b-15b

3a>-13b

a>-13b/3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
√48a^4 b^5 c^3 d simplify and keep it in radical form
Morgarella [4.7K]
I will assume the square root extends all the way across.

\sqrt{48a^4b^5c^3}

\sqrt{2^4\cdot3\cdot a^4b^5c^3}

\sqrt{(2^2)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4\cdot a^2 \cdot b^2 \cdot c)^2\cdot3\cdot b\cdot c}

4\cdot a^2\cdot b^2\cdot c\sqrt{3\cdot b\cdot c}

\boxed{4a^2b^2c\sqrt{3bc}}






3 0
3 years ago
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