Answer:
a=1.25m/s²
Explanation:
GIVEN DATA
vi=10m/s
vf=15m/s
S=5m
TO FIND
a=?
SOLUTION
by using third equation of motion
2as=(vf)²-(vi)²
2a(5m)=(15m/s)²-(10m/s)²
10m×a=225m²/s²-100m²/s²
10m×a=125m²/s²
a=
a=12.5m/s²
They appreciate art and music
Answer:
61.76 N.
Explanation:
Given the mass of the car, m = 1.60 kg.
The speed of the car, v = 12.0 m/s.
The radius of the circle, r = 5 m.
As car is moving in circular motion, so net force ( normal force + weight of the car) is equal to centripetal force enables the car to reamins in circular path.
Let N is the normal force.
So,
Now substitute the given values, we get
N = 61.76 N.
Thus, the magnitude ofthe normal force exerted on the car by the walls is 61.76 N.
Answer:
18feet
Explanation:
We need to find the distance,c between the vertex and the focus.
For a vertical parabola:
#If we place our parabola at the center, the expression changes to:
The points of the parabola are given as (12,2), substitute in our equation to find c:
Hence, the receiver should be placed at 18ft
Answer:
Gravity holds stars together and keeps us on the ground. The electromagnetic force ensures the stability of atoms and makes chemistry happen. The strong nuclear force holds the kernels of matter, atomic nuclei, together, and powers the burning of stars.
Explanation: