7. What is the kinetic energy of a 3-kilogram ball that is rolling at 2 meters per second?

The lens-makers’ equation applies to a lens immersed in a liquid if n in the equation is replaced by n2/n1. Here n2 refers to th

pickupchik [31]

Answer:

a

The focal length of the lens in water is $f_{water} = 262.68 cm$

b

The focal length of the mirror in water is $f =79.0cm$

Explanation:

From the question we are told that

The index of refraction of the lens material = $n_2$

The index of refraction of the medium surrounding the lens = $n_1$

The lens maker's formula is mathematically represented as

$\frac{1}{f} = (n -1) [\frac{1}{R_1} - \frac{1}{R_2} ]$

Where $f$ is the focal length

$n$ is the index of refraction

$R_1 and R_2$ are the radius of curvature of sphere 1 and 2 of the lens

From the question When the lens in air we have

$\frac{1}{f_{air}} = (n-1) [\frac{1}{R_1} - \frac{1}{R_2} ]$

When immersed in liquid the formula becomes

$\frac{1}{f_{water}} = [\frac{n_2}{n_1} - 1 ] [\frac{1}{R_1} - \frac{1}{R_2} ]$

The ratio of the focal length of the the two medium is mathematically evaluated as

$\frac{f_water}{f_{air}} = \frac{n_2 -1}{[\frac{n_2}{n_1} - 1] }$

From the question

$f_{air }$ = 79.0 cm

$n_2 = 1.55$

and the refractive index of water(material surrounding the lens) has a constant value of $n_1 = 1.33$

$\frac{f_{water}}{79} = \frac{1.55- 1}{\frac{1.55}{1.44} -1}$

$f_{water} = 262.68 cm$

b

The focal length of a mirror is dependent on the concept of reflection which is not affected by medium around it.

7 0

3 years ago

You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between

Murljashka [212]

Answer:

a) v = 0.0496 m / s , b) v = 0.0957 m / s

Explanation:

a) in this case we have an inelastic collision,

To solve these problems, the most important thing is to define the system formed by all the bodies, so that the forces during the crash have been internal and the amount of movement is conserved.

Therefore the system is made up of the ball and the player

initial instant. Before catching the ball

p₀ = m v₁

final moment. After you have grabbed the ball

$p_{f}$ = (m + M) v

the moment is preserved

po = p_{f}

m v₁ = (m + M) v

v = m / (m + M) v₁

let's calculate

v = 0.405 / (0.405 + 69) 8.50

v = 0.0496 m / s

in the same direction that the ball takes

b) In this case the ball bounces with a speed of V₂ = -7.80 m / s, the negative sign is because it is going in opposite directions

let's write the moment in two times

initial instant. Before the crash

p₀ = m v₁

try end. Right after the crash

p_{f} = m v₂ + M v

the moment is preserved

p₀ = p_{f}

m v₁ = m v₂ + M v

v = m (v₁ -v₂) / M

v = 0.405 /69 (8.50 - (7.80))

v = 0.0957 m / s

in the initial direction of the ball

8 0

3 years ago

Given a force of 75N and an acceleration of 3m/s2, what is the mass

Ivahew [28]

force = 75N --- (<em>g</em><em>i</em><em>v</em><em>e</em><em>n</em><em>)</em>

acceleration = 3m/s² ---- (<em>g</em><em>i</em><em>v</em><em>e</em><em>n</em><em>)</em>

<h3>FORCE = mass × acceleration</h3>

75N = mass × 3m/s²

mass = 75÷3

<h3>mass = 25kg</h3><h2>-----------------------------</h2><h2>FOLLOW ME</h2>

6 0

3 years ago

In which way does blue light change as it travels

____ [38]

Blue light changes as it travels from diamond into crown glass at its speed increases.

7 0

3 years ago

Read 2 more answers

I need help with question 8 .

Vesnalui [34]

The bike is maintaining "constant velocity". He's moving at 15 m/s when we see him for the first time, 15 m/s later that day, and 15 m/s next week.

The car starts from zero, and goes 4.0 m/s FASTER each second. After one second, it's going 4.0 m/s. After 2 seconds, it's going 8 m/s. And after 3 seconds, it's going 12 m/s.

This is the point at which the question wants us to compare them ... 3 seconds. The bike is moving at 15 m/s and the car has sped up to 12 m/s. <em>The bike is moving faster than the car.</em>

If we hung around and kept watching for another second, the car would then be moving at 16 m/s, and would be moving faster than the bike. But we lost interest after answering the question, and we left at 3 seconds.

5 0

3 years ago