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3 years ago

(will mark brainliest)Which of the following has the most potential energy?

Physics

2 answers:

Anastasy [175]3 years ago

7 0

A car speeding down a 20 foot hill

Mashcka [7]3 years ago

5 0

The correct answer is a car at the top of a 20 foot hill.

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If a liquid is heated and the temperature at which it boils is measured, the _____ property is being measured.

igor_vitrenko [27]

Answer: atomic think so

Explanation:

5 0

3 years ago

Read 2 more answers

Which statement(s) correctly compare the masses of protons, neutrons, and electrons? Check all that apply

umka21 [38]

__Protons and neutrons have similar mass.

__Electrons are smaller than a proton or a neutron.

Explanation:

The three particles involved in this problem are:

Proton: it is positively charge, it is found in the nucleus of the atom, and its mass is $m_p = 1.67 \cdot 10^{-27} kg$
Neutron: it has no electric charge, it is also found in the nucleus of the atom, and its mass is approximately equal to that of the proton (just slightly larger)
Electron: it has negative electric charge, it orbit around the nucleus of the atom, and its mass is much smaller than that of the proton: $m_e = 9.11 \cdot 10^{-31} kg$

We can now analyze each of the given statement:

__Protons and neutrons have similar mass. --> TRUE

__Protons and electrons have similar mass. --> FALSE, the electron is much lighter

__Neutrons and electrons have similar mass. --> FALSE, the neutron is much heavier

__Protons are smaller than a neutron or an electron. --> FALSE, protons are similar to the neutrons

__Neutrons are smaller than a proton or an electron. --> FALSE, neutrons are similar to the protons

__Electrons are smaller than a proton or a neutron. --> TRUE

Learn more about atoms:

brainly.com/question/2757829

#LearnwithBrainly

3 0

3 years ago

Read 2 more answers

Which cell part are red blood cells missing

12345 [234]

They lack a cell nucleus.

3 0

3 years ago

How long must a current of 100mA flow so as to transfer a charge of 80 C?

defon

Answer:

800s

Explanation:

Q=It

where,

Q=80c

I =100MA=0.1A

t=?

Q=It

800=0.1×t

t=80×0.1

t=800s

6 0

3 years ago

Read 2 more answers

Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.

elena-s [515]

Answer:

$g=13.42\frac{m}{s^2}$

Explanation:

1) Notation and info given

$\rho_{center}=13000 \frac{kg}{m^3}$ represent the density at the center of the planet

$\rho_{surface}=2100 \frac{kg}{m^3}$ represent the densisty at the surface of the planet

r represent the radius

$r_{earth}=6.371x10^{6}m$ represent the radius of the Earth

2) Solution to the problem

So we can use a model to describe the density as function of the radius

$r=0, \rho(0)=\rho_{center}=13000 \frac{kg}{m^3}$

$r=6.371x10^{6}m, \rho(6.371x10^{6}m)=\rho_{surface}=2100 \frac{kg}{m^3}$

So we can create a linear model in the for y=b+mx, where the intercept b= $\rho_{center}=13000 \frac{kg}{m^3}$ and the slope would be given by $m=\frac{y_2-y_1}{x_2-x_1}=\frac{\rho_{surface}-\rho_{center}}{r_{earth}-0}$

So then our linear model would be

$\rho (r)=\rho_{center}+\frac{\rho_{surface}-\rho_{center}}{r_{earth}}r$

Since the goal for the problem is find the gravitational acceleration we need to begin finding the total mass of the planet, and for this we can use a finite element and spherical coordinates. The volume for the differential element would be $dV=r^2 sin\theta d\phi d\theta dr$ .

And the total mass would be given by the following integral

$M=\int \rho (r) dV$

Replacing dV we have the following result:

$M=\int_{0}^{2\pi}d\phi \int_{0}^{\pi}sin\theta d\theta \int_{0}^{r_{earth}}(r^2 \rho_{center}+\frac{\rho_{surface}-\rho_{center}}{r_{earth}}r)$

We can solve the integrals one by one and the final result would be the following

$M=4\pi(\frac{r^3_{earth}\rho_{center}}{3}+\frac{r^4_{earth}}{4} \frac{\rho_{surface}-\rho_{center}}{r_{earth}})$

Simplyfind this last expression we have:

$M=\frac{4\pi\rho_{center}r^3_{earth}}{3}+\pi r^3_{earth}(\rho_{surface}-\rho_{center})$

$M=\pi r^3_{earth}(\frac{4}{3}\rho_{center}+\rho_{surface}-\rho_{center})$

$M=\pi r^3_{earth}[\rho_{surface}+\frac{1}{3}\rho_{center}]$

And replacing the values we got:

$M=\pi (6.371x10^{6}m)^2(\frac{1}{3}13000 \frac{kg}{m^3}+2100 \frac{kg}{m^3})=8.204x10^{24}kg$

And now that for any shape the gravitational acceleration is given by:

$g=\frac{MG}{r^2_{earth}}=\frac{(6.67408x10^{-11}\frac{m^3}{kgs^2})*8.204x10^{24}kg}{(6371000m)^2}=13.48\frac{m}{s^2}$

4 0

3 years ago