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Valentin [98]
3 years ago
14

A force causes a mass of 4 kg to have an acceleration of 8 m/s2. Suppose something causes the mass to be one-quarter of its orig

inal amount. What will happen to the acceleration if the amount of force used remains the same?
Physics
1 answer:
solniwko [45]3 years ago
5 0

Explanation:

From Newton's second law:

F = ma

Given that m = 4 kg and a = 8 m/s²:

F = (4 kg) (8 m/s²)

F = 32 N

If m is reduced to 1 kg and F stays at 32 N:

32 N = (1 kg) a

a = 32 m/s²

So the acceleration increases by a factor of 4.

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Tasya [4]

Answer:

The pressure is p_1 = 4051.4 \ Pa

Explanation:

From the question we are told that

     The gauge pressure at the mouth is  p_1

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    The speed of the liquid outside the body is  v_2 =  3.1 \ m/s

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So

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Now the height of inside the mouth is  h_1 =  d =  2r_1 =  2* 0.04 =  0.08\ m

Now the height of the column is  h_2 =  d =  2r_2 =  2* 0.004 =  0.008\ m

Generally according to Bernoulli's  equation

        p_1 =  [\frac{1}{2}  \rho v_2^2 + h_2 \rho g +p_2] -[\frac{1}{2} \rho * v_1^2 + h_1 \rho g ]

Now  \rho =  1000 \ kg m^{-3} which is the density of water

        p_2 is the gauge pressure of the atmosphere which is  zero

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       p_1 =  [(0.5 * 1000 * (3.1)^2) +(0.008 * 1000 * 9.8) + 0]-

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       p_1 = 4051.4 \ Pa

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