Answer:
1370
Step-by-step explanation:
<h3>Given</h3>
- AP with d= 7 and a₂₂ = 149
<h3>To find</h3>
<h3>Solution</h3>
<u>First, let's get the value of the first term:</u>
- aₙ = a + (n-1)d
- a₂₂ = a + 21d
- 149 = a + 21*7
- a = 149 - 147
- a= 2
<u>Next, let's find the sum of the first 20 terms</u>
- Sₙ = 1/2n(2a+ (n-1)d)
- S₂₀ = 1/2*20(2*2 + 19*7) = 10(4 + 133) = 10*137 = 1370
<u>Answer is</u> 1370
Step-by-step explanation:
The Taylor series expansion is:
Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!
f(x) = 1/x, a = 4, and n = 3.
First, find the derivatives.
f⁽⁰⁾(4) = 1/4
f⁽¹⁾(4) = -1/(4)² = -1/16
f⁽²⁾(4) = 2/(4)³ = 1/32
f⁽³⁾(4) = -6/(4)⁴ = -3/128
Therefore:
T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!
T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³
f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0. So we can eliminate the top left option. That leaves the other three options, where f(x) is the blue line.
Now we have to determine which green line is T₃(x). The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).
The bottom right graph is the only correct option.
Answer:
87 is the number
Step-by-step explanation:
Answer: 166
Step-by-step explanation:
Number of trophies = 3
Total Legos required for all trophies = 324
Number of Legos for largest trophy(A) = 220
Number of Legos for smallest trophy(B) = 135
Number of Legos required for final trophy(C)
=?
Total Legos = [Number of Legos for largest trophy(A) + Number of Legos for smallest trophy(B) + Number of Legos required for final trophy(C)]
324 = 220 +135 + C
324 = 355 + C
324 - 355 = C
-31 = C
135 + 31 = 166
