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3 years ago

Is the point (3, 11) a solution for the linear equation 1/3x + y = 12? Explain.

Mathematics

1 answer:

PtichkaEL [24]3 years ago

5 0

9514 1404 393

Answer:

yes

Step-by-step explanation:

The point is on the line.

The coordinate values satisfy the equation:

1/3x + y = 12

1/3(3) + 11 = 12 . . . substitute for x and y

1 + 11 = 12 . . . . . . . true

Any point that satisfies the equation is a solution. (3, 11) is a solution.

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Paul opened a bakery. The net value of the bakery (in

Umnica [9.8K]

Answer:

1) 2(t - 7)(t + 1)

2) $32,000

Step-by-step explanation:

v(t) = 2t² - 12t - 14

v(t) = 2(t² - 6t - 7) = 2(t - 7)(t + 1)

x = -b/2a = 6/2 = 3

y = 2(3)² - 12(3) - 14 = -32

(3, -32) means at 3 months, -32 thousand dollars

7 0

3 years ago

Read 2 more answers

Subtract the sum of (5^3 + 7^2 − 9) and (7 + 3^2 ) from the sum of (5^3 + 6) and (10^2 − 12)

ollegr [7]

Given:

Subtract the sum of $(5^3 + 7^2-9)$ and $(7 + 3^2)$ from the sum of $(5^3 + 6)$ and $(10^2-12)$ .

To find:

The simplified value for the given statement.

Solution:

The sum of $(5^3 + 7^2-9)$ and $(7 + 3^2)$

$Sum_1=5^3+7^2-9+7 + 3^2$

$Sum_1=125+49-9+7 + 9$

$Sum_1=181$

The sum of $(5^3 + 6)$ and $(10^2-12)$ .

$Sum_2=5^3 + 6+10^2-12$

$Sum_2=125+6+100-12$

$Sum_2=219$

Now, subtract $Sum_1$ from $Sum_2$ .

$219-181=38$

Therefore, the required value after the subtraction is 38.

8 0

3 years ago

Simplify arccot sqroot of 3/3

enyata [817]

The simplified version of arccot sqroot 3/3 is $\frac{ \pi }{4}$

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3 years ago

A runner runs around a circular track. He completes one lap at a time of t = 269 s at a constant speed of v = 4.6 m/s. What is t

AURORKA [14]

Answer:

$\boxed{\text{197 m}}$

Step-by-step explanation:

The formula relating distance (d), speed (s), and time (t) is

d = st

1. Calculate the distance

d = 269 s × 4.6 m·s⁻¹ = 1240 m

2.Calculate the track radius

The distance travelled is the circumference of a circle

$\begin{array}{rcl}C & = & 2 \pi r\\1240 & = & 2 \pi r\\\\r & = & \dfrac{1240}{2 \pi }\\\\& = & 197\\\end{array}\\\text{The radius of the track is }\boxed{\textbf{197 m}}$

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4 years ago

Plz help

12345 [234]

Answer:

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3 years ago