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Paraphin [41]
3 years ago
7

What is the following quotient? sqrt 6 + sqrt 11 / sqrt 5 +sqrt 3

Mathematics
2 answers:
Nadya [2.5K]3 years ago
6 0

The answer is B) Link below

just olya [345]3 years ago
5 0

Answer:

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

Step-by-step explanation:

Let's translate what you've written in words to an expression with mathematical symbols.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}}

To solve this, you need to multiply both the numerator and denominator with the conjugate of the denominator.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

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Use the net to find the approximate surface area of the cylinder to the nearest square meter.
lyudmila [28]

Answer: D

Step-by-step explanation:

Formula= 2piRh +2piR^2

2pi*7*11 + 2pi*49 = 791.68 or 792

4 0
3 years ago
Read 2 more answers
I NEED HELP NOW PLS ASAP
castortr0y [4]

Answer:

Step-by-step explanation:

hello,

I understand that there are only 4 cards  and then the player draw a card out of the 4 cards, replace it so the second draw is still out of the 4 cards

<u>How many ways can you draw two cards?</u>

as the first card is replaced, this is 4*4=16

so there is 16 possibles ways

hearts hearts

hearts clubs

hearts diamonds

hearts spades

clubs hearts

clubs clubs

clubs diamonds

clubs spades

diamonds hearts

diamonds clubs

diamonds diamonds

diamonds spades

spades hearts

spades clubs

spades diamonds

spades spades

<u>out of these 16 ways, how many have same colour for both cards?</u>

I assume that there are only two colours Red and Black, so we can have

only 8 ways so the first probability is 8/16 = 1/2

<u>out of these 16 ways, how many are red ace first and black ace?</u>

There are 4 ways so the probability is 4/16 = 1/4

hope this helps

8 0
2 years ago
Read 2 more answers
(3,1)(2,0)(1,-1)(3,2)(2,1)(1,0) A: Function OB: Not a function​
levacccp [35]

Answer:

Not a function

Step-by-step explanation:

Y values can repeat in a function but domain cannot. 3 is repeated twice, thus these values do not represent a function.

4 0
3 years ago
When finding the 9th term in a geometric sequence with a common ratio of 2 and a first
Zarrin [17]

Answer:

8

Step-by-step explanation:

Nth term of a geometric sequence is given as:

t_n = a r^{(n-1)} ...(1)

Plugging n = 9, a = 3 and r = 2 in the above equation, we find:

t_9 = (3) (2)^{9-1}

t_9 = (3) (2)^{8}... (2)

Comparing equations (1) & (2), we obtan:

(n - 1) = 8

5 0
3 years ago
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
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