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Paraphin [41]
3 years ago
7

What is the following quotient? sqrt 6 + sqrt 11 / sqrt 5 +sqrt 3

Mathematics
2 answers:
Nadya [2.5K]3 years ago
6 0

The answer is B) Link below

just olya [345]3 years ago
5 0

Answer:

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

Step-by-step explanation:

Let's translate what you've written in words to an expression with mathematical symbols.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}}

To solve this, you need to multiply both the numerator and denominator with the conjugate of the denominator.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

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Which of the binomials below is a factor of this trinomial?<br> x^2- 14x+ 24
Ray Of Light [21]

Answer:

(x-2)(x-12)

Step-by-step explanation:

x^2-14x+24=(x-2)(x-12)

5 0
3 years ago
The common ratio in a geometric series is 4 and the first term is 3.
kodGreya [7K]

Answer:

The sum of the first 8 terms in the series is 65535.

Step-by-step explanation:

We have,

The common ratio in a geometric series, r = 4

First term of GP is, a = 3

It is required to find the sum of the first 8 terms in the series. The sum of first n terms of a GP is given by :

S_n=\dfrac{a(r^n-1)}{r-1}, r>1

Here, n = 8

S_8=\dfrac{3\times ((4)^8-1)}{4-1}\\\\S_8=65535

So, the sum of the first 8 terms in the series is 65535.

3 0
3 years ago
What is the coefficient of the term 12p+9q
olga nikolaevna [1]

Answer:

The answer is 12.  

Step-by-step explanation:

12 is the coefficient because it is the number multiplied by the variable p in the equation.

I hope this helps u! :D

4 0
3 years ago
10
Archy [21]

Answer: 5h+9

Step-by-step explanation:

10h + (-5h)

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6 0
2 years ago
Y^2-y-42<br> pls helpppppp i dunno how to do this one??
beks73 [17]
(y-7)(y+6)
Hopefully this is right :)
6 0
3 years ago
Read 2 more answers
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