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Setler79 [48]
3 years ago
10

Stephanie has 6 classes a day at school. Each class is 52 minutes long. She goes to school 5 days a week. How much time does she

spend class each day? show two different ways to solve this problem
Mathematics
1 answer:
densk [106]3 years ago
4 0

Answer:

t=312 minutes or t=5.2hrs

Step-by-step explanation:

I.Given that Stephanie has 6 classes a day of 52 minutes each.

-To get the duration spent in class each day, we multiply the total number of classes per day by the duration per class:

t=C_tD_c, C_t=6, D_c=52\\\\t=6\times 52\\\\=312 \ mins

Stephanie spends 312 minutes per day in class

II. Get the duration in Hours:

#We multiply the class duration by number of class then divide by 60 minutes to get total duration in hours:

t=C_tD_c, C_t=6, D_c=52\\\\t=6\times 52\\\\=312 \ mins\times\frac{1\ hr}{60\ min}\\\\=5.2\ hrs

Stephanie spends 5.2hrs per day in class

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a. The positive difference between Nelson's height and the population mean is: \\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in.

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Step-by-step explanation:

The key concept to answer this question is the z-score. A <em>z-score</em> "tells us" the distance from the population's mean of a raw score in <em>standard deviation</em> units. A <em>positive value</em> for a z-score indicates that the raw score is <em>above</em> the population mean, whereas a <em>negative value</em> tells us that the raw score is <em>below</em> the population mean. The formula to obtain this <em>z-score</em> is as follows:

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From the question, we have that:

  • Nelson's height is 68 in. In this case, the raw score is 68 in \\ x = 68 in.
  • \\ \mu = 70.7in.
  • \\ \sigma = 2.3in.

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a. What is the positive difference between Nelson​'s height and the​ mean?

The positive difference between Nelson's height and the population mean is (taking the absolute value for this difference):

\\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in.

That is, <em>the positive difference is 2.7 in</em>.

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To find how many <em>standard deviations</em> is that, we need to divide that difference by the <em>population standard deviation</em>. That is:

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In words, the difference found in part (a) is 1.174 <em>standard deviations</em> from the mean. Notice that we are not taking into account here if the raw score, <em>x,</em> is <em>below</em> or <em>above</em> the mean.

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Using formula [1], we have

\\ z = \frac{x - \mu}{\sigma}

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This z-score "tells us" that Nelson's height is <em>1.174 standard deviations</em> <em>below</em> the population mean (notice the negative symbol in the above result), i.e., Nelson's height is <em>below</em> the mean for heights in the club presidents of the past century 1.174 standard deviations units.

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\\ -2 < z_{Nelson} < 2

\\ -2 < -1.174 < 2

Then, Nelson's height is <em>usual</em> according to that statement.  

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