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erik [133]
4 years ago
14

Ta Os Rh create what metal non metal metalloid or gas

Chemistry
1 answer:
Harrizon [31]4 years ago
4 0

Tantalum (Ta), Osmium (Os) and Rhodium (Rh) are metals.

<u>Explanation</u>:

  • Metals are good conductors of heat and electricity and they can be hammered into sheets (malleable).Mainly most of them are solids. Ta, Os and Rh are all metals with a same platinum group.
  • Tantalum (Ta) with a atomic number 73 is a lustrous transition metal which is highly corrosive resistant. It is mainly used in making electronic equipment.
  • Rhodium (Rh) is a chemical element with atomic number 45 is a rare, silvery white,hard and corrosive resistant metal. Osmium (Os) with a atomic number 76 is a hard, brittle bluish-white transition metal.

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URGENT PLEASE HELP ILL MARK BRAINLIST Please someone look at the graph and tell me how to fill in the blank like you don't need
Taya2010 [7]

Answer:

Filled below

Explanation:

#v.e means number of valence electrons.

Also, the column total v.e is gotten by adding the v.e of the metal to the v.e of the non metal based on the chemical formula of both of the 2 elements combined.

K: Cl: 5; KCl; 1 + 5 = 6

Be: S: 6; BeS; 2 + 6 = 8

Na: F: 7; NaF; 1 + 7 = 8

Mg: Se: MgSe; 2 + 6 = 8

Al; N; AlN; 1 + 5 = 6

Be; F; BeF2; 2 + 2(7) = 16

Mg; N; Mg3N2; 3(2) + 2(7) = 20

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3 years ago
How can you separate a liquid from a liquid?
Yakvenalex [24]
We can use distillation to separate liquid to liquid
7 0
4 years ago
Besides drinking water, how is water helpful for life and nature?
Contact [7]

Answer:

It keeps us alive, helps us grow plants, helps plants thrive, gives us food, helps keep our animals and crops healthy, cleans us, and so much more

Explanation:

5 0
2 years ago
What is the entropy of this collection of training examples with respect to the positive class B. What are the information gains
Alenkinab [10]

The data set is missing in the question. The data set is given in the attachment.

Solution :

a). In the table, there are four positive examples and give number of negative examples.

Therefore,

$P(+) = \frac{4}{9}$   and

$P(-) = \frac{5}{9}$

The entropy of the training examples is given by :

$ -\frac{4}{9}\log_2\left(\frac{4}{9}\right)-\frac{5}{9}\log_2\left(\frac{5}{9}\right)$

= 0.9911

b). For the attribute all the associating increments and the probability are :

  $a_1$   +   -

  T   3    1

  F    1    4

Th entropy for   $a_1$  is given by :

$\frac{4}{9}[ -\frac{3}{4}\log\left(\frac{3}{4}\right)-\frac{1}{4}\log\left(\frac{1}{4}\right)]+\frac{5}{9}[ -\frac{1}{5}\log\left(\frac{1}{5}\right)-\frac{4}{5}\log\left(\frac{4}{5}\right)]$

= 0.7616

Therefore, the information gain for $a_1$  is

  0.9911 - 0.7616 = 0.2294

Similarly for the attribute $a_2$  the associating counts and the probabilities are :

  $a_2$  +   -

  T   2    3

  F   2    2

Th entropy for   $a_2$ is given by :

$\frac{5}{9}[ -\frac{2}{5}\log\left(\frac{2}{5}\right)-\frac{3}{5}\log\left(\frac{3}{5}\right)]+\frac{4}{9}[ -\frac{2}{4}\log\left(\frac{2}{4}\right)-\frac{2}{4}\log\left(\frac{2}{4}\right)]$

= 0.9839

Therefore, the information gain for $a_2$ is

  0.9911 - 0.9839 = 0.0072

$a_3$     Class label      split point       entropy        Info gain

1.0         +                        2.0            0.8484        0.1427

3.0        -                         3.5            0.9885        0.0026

4.0        +                        4.5            0.9183         0.0728

5.0        -

5.0        -                        5.5            0.9839        0.0072

6.0        +                       6.5             0.9728       0.0183

7.0        +

7.0        -                        7.5             0.8889       0.1022

The best split for $a_3$  observed at split point which is equal to 2.

c). From the table mention in part (b) of the information gain, we can say that $a_1$ produces the best split.

4 0
3 years ago
Which describes any substance that shatters or breaks easily?
Daniel [21]

Answer:

Brittle

Explanation:

3 0
3 years ago
Read 2 more answers
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