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Firdavs [7]
2 years ago
13

How many grans of NaoH Are needed to neutralize grans of H2So4​

Chemistry
1 answer:
user100 [1]2 years ago
5 0

Answer :]

to convert from g NaOH to mol NaOH. = 1.48 g NaOH are needed to neutralize the acid.

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10Al + 6NH4ClO4 → 4Al 2O3 + 2AlCl 3 + 12H2O + 3N2
Zolol [24]
1 Aluminium is oxidised Al - 3e = Al⁺³

2 Chlorine is reduced  Cl⁺⁷ + 8e = Cl⁻¹

3 Nitrogen is oxidised 2N⁻³ - 6e = N₂

4 0
3 years ago
What is the percent composition of the u.s quarter, which has the mass of 5.670g
Vitek1552 [10]
The percent composition of each element can be calculated as follows:
% composition = (mass of element / total mass) * 100

The total mass of the quarter is given to be 5.670 grams
Mass of Cu = 5.198 grams
Mass of Ni = 0.472 grams

Substitute in the above equation to get the mass percentage of each element as follows:
% of Cu = (5.198/5.670) * 100 = 91.675%
% of Ni = (0.472/5.670) * 100 = 8.325%
6 0
3 years ago
Carrying capacity is _____.
Alinara [238K]
<span>Carrying capacity is the number of organisms an ecosystem can support. It is the maximum size of a population that can survive in the ecosystem. If the animals reach the carrying capacity, the population may crash. As the consequence, the number of animals will decrease due to predators or diseases.</span>
5 0
3 years ago
Read 2 more answers
If there were an element above fluorine in the periodic table what phase would you expect it to be in (at room temp)?
AysviL [449]

If there were an element above fluorine, its state would be a gas. This is because fluorine is located in the non-metal section of the periodic table which can all be found as a gas at room temperature.

3 0
3 years ago
If have a volume of 18 L of a gas at a temperature of 272 K and a pressure of 90 atm, what will be the pressure of the gas if ra
Solnce55 [7]

Answer:

P₂ ≅ 100 atm (1 sig. fig. based on the given value of P₁ = 90 atm)

Explanation:

Given:

P₁ = 90 atm                    P₂ = ?

V₁ = 18 Liters(L)              L₂ = 12 Liters(L)      

=> decrease volume => increase pressure

=> volume ratio that will increase 90 atm is (18L/12L)                                                                  

T₁ = 272 Kelvin(K)          T₂ = 274 Kelvin(K)

=>  increase temperature => increase pressure

=> temperature ratio that will increase 90 atm is (274K/272K)

n₁ = moles = constant    n₂ = n₁ = constant

P₂ = 90 atm x (18L/12L) x (274K/272K) = 135.9926471 atm (calculator)

By rule of sig. figs., the final answer should be rounded to an accuracy equal to the 'measured' data value having the least number of sig. figs. This means P₂ ≅ 100 atm based on the given value of P₁ = 90 atm.

3 0
3 years ago
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