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r-ruslan [8.4K]
3 years ago
12

Methanol (CH3OH) has a boiling point of -97°C. Methane (CH4) has a boiling point of -162°C. Which type of bonding explains why m

ethanol has a much higher boiling point than methane?
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
6 0

Answer is: hydrogen bonding.

Methanol has stronger intermolecular bonds than methane.

Intermolecular forces are the forces between molecules or particles.

There are several types of intermolecular forces: hydrogen bonding, ion-induced dipole forces, ion-dipole forces andvan der Waals forces.

Hydrogen bond is an electrostatic attraction between two polar groups that occurs when a hydrogen atom (H), covalently bound to a highly electronegative atom such as flourine (F), oxygen (O) and nitrogen (N) atoms.

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Draw the product(s) that are expected when tert-butyl bromide undergoes solvolysis in isopropanol, (CH3)2CHOH.
N76 [4]
Those reactions in which Alkyl Halide reacts with the solvent without the involvement of any acid or base is called as Solvolysis. In given problem <em>tert</em>-Butyl Bromide is a tertiary Alkyl Halide and we know well that tertiary alkyl halides undergo SN¹ and E¹ elimination reaction due to the formation of stable tertiary carbocation. In given example after the formation of carbocation when Isopropyl act as nucleophile it will produce ether and when it acts as a base it will produce unsaturated compound. The reaction along with both products is shown below,

5 0
3 years ago
Read 2 more answers
Calculate the volume of one mole of a gas at 1.00 atm pressure and 0 °C.
N76 [4]

Answer:

Solution:-

The gas is in the standard temperature and pressure condition i.e. at S.T.P

Therefore,

V

i

​

=22.4dm

3

V

f

​

=?

As given that the expansion is isothermal and reversible

∴ΔU=0

Now from first law of thermodynamics,

ΔU=q+w

∵ΔU=0

∴q=–w

Given that the heat is absorbed.

∴q=1000cal

⇒w=−q=−1000cal

Now,

Work done in a reversible isothermal expansion is given by-

w=−nRTln(

V

i

​

V

f

​

​

)

Given:-

T=0℃=273K

n=1 mol

∴1000=−nRTln(

V

i

​

V

f

​

​

)

⇒1000=−1×2.303×2×273×log(

22.4

V

f

​

​

)

Explanation:

6 0
3 years ago
Chlorination of ethane yields, in addition to ethyl chloride, a mixture of two isomeric dichlorides. what are the structures of
jeyben [28]
CH_3 CH_2 Cl has two different types of hydrogen. On further chlorination they are being substituted by chlorine to give two isomeric dichlorides

The structures of the two chlorides are shown below.

Where Hb is replaced by Cl and Ha is replaced by Cl

5 0
4 years ago
PLEASE ANSWER Which is/are true?
Alona [7]

You have to check each statement, so this is equivalent to 5 different questions.

<u>Answers:</u>

The true statements are:

  • b. Si has valence electrons in the n = 3 energy level.

  • d. Xe has valence electrons in the n = 5 energy level.

<u>Explanations:</u>

<u>a. Li has valence electrons in the n = 1 energy level.</u>

  • <u>Answer: False.</u>

<em>Valence electrons</em> are the electrons in the outermost main energy level (shell of electrons).

To determine where the valence electrons are, you build the electron configuration, using Aufbau rules to predict the orbital filling: in increasing order of energy.

The atomic number of lithium (Li) is 3. Hence, you have to distribute 3 electrons, and so its electron confiuration is:

  • 1s² 2s¹

The only valence electron is in the 2s orbital, i.e. in the n = 2 energy level.

<u>b. Si has valence electrons in the n = 3 energy level.</u>

  • <u>Answer: True</u>

Silicon (Si) has atomic number 14, so you have to distribute 14 electrons in increasing order of energy:

  • 1s² 2s² 2p⁶ 3s² 3p²

Thus, Si has five valence electrons, and they are in the n = 3 energy level.

<u>c. Ga has valence electrons in the n = 3 energy level.</u>

  • <u>Answer: False</u>

Gallium has atomic number 31, so you have to distribute 31 electrons, filling the orbitals in increasing order of enery.

  • 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p¹

The highest energy level is 4. This is where the valence electrons are. So, Ga has the valence electrons in the n = 4 level (not n = 3 as the statement describes).

<u>d. Xe has valence electrons in the n = 5 energy level.</u>

  • <u>Answer: True</u>

The atomic number of Xe is 54.

Using the short notation (noble gas notation), and filling the orbitals in increasing order of energy, you get the configuration:

  • [Kr] 5s² 4d¹⁰ 5p⁶.

Hence, the valence electrons are in the n ) 5 level, such as the statement describes.

<u>e. P has valence electrons in the n = 2 energy level.</u>

  • <u>Answer: False</u>

Phosphorus (P) has atomic number 15, hence there are 15 electrons.

The electron configuration following the increasing order of energy, which you can remember using Aufbau rules, is:

  • 1s² 2s² 3s² 3p³

Then, the valence electrons are in the n = 3 energy level; not in the n = 2 energy level.

3 0
3 years ago
What is the molar mass of (NH4)2S
Anastaziya [24]

Answer:

This compound is Ammonium Sulphide and has molar mass 68 g/mol.

Explanation:

  • Molar Mass : It is the mass of 1 mole of the substance and in grams.Its units are gram/mole.
  • It is numerically equal to mass of the substance in atomic mass units

How to calculate Molar mass :

(NH_{4})_{2}S = 2(atomic\ mass\ of\ N + 4\times mass\ of\ H ) +atomic\  mass\ of\ S

(NH_{4})_{2}S = 2(14 + 4(1) ) + 32

(NH_{4})_{2}S = 2(14 + 4 ) + 32

(NH_{4})_{2}S = 2(18) + 32

(NH_{4})_{2}S = 36 + 32

(NH_{4})_{2}S = 68 grams/mole

Molar mass of Ammonium sulphide is 68 g/mol

8 0
3 years ago
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