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sergiy2304 [10]
3 years ago
11

How many O2 molecules can be made with the oxygen from 492 g of sodium phosphate?

Chemistry
2 answers:
serg [7]3 years ago
7 0
<span>To answer this question, you need to change the sodium phosphate unit into mol and doing the reaction. Sodium phosphate or Na3PO4  molecular weight is 163.94 or 164 rounded up. Then the amount should be: 492g/ (164g/mol)= 3 mol

For every 1 mol of </span>Na3PO4  there are 4 mol of oxygen element. To made 1 mol of O2 molecule, you will need 2 mol oxygen element. Then the amount of oxygen should be: 4/2 * 3 mol= 6 mol * 6.02 * 10^23= 36.12 * 10*23= 3.61 * 10^24

erma4kov [3.2K]3 years ago
6 0
We must analyze how are we going to convert the given mass of sulfur into molecules of oxygen. Oxygen has a subscript of 2. It means that it has two atoms per molecule. Which means, there are
7.37
x
10
22
molecules but
12.04
x
10
22
atoms of oxygen
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A student has two compounds in two separate bottles but with no labels on either one. One is an unbranched alkane, octane, C8H18
Aleks [24]

Answer:

a) both substances are insoluble in water

b) both substances are soluble in ligroin

c) both substances suffer combustion, octane produces more CO₂ than hexene.

d) both substances are less dense than waterl, with hexene having the lowest density.

e) only hexene would react with bromine

f)  only hexene would react with permanganate

Explanation:

a) both substances are non-polar and water is polar

b) both substances are non-polar and lingroin is non-polar

c) C₈H₁₈ + 17.5O₂ → 8CO₂ + 9H₂O

    C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O

d) water = 997 kg/m³

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e) bromine test is used to detect unsaturations

f) permanganate test is used to detect unsaturations

7 0
3 years ago
Write the electronic configuration of Cr^2+ (z=24) and predict the number of electrons having n+1 value equal to 3
leonid [27]

Answer:

(a) Cr²⁺: 1s² 2s²2p⁶ 3s²3p⁶ 3d⁴; (b) eight  

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(a) Electron configuration of Cr

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It's Element 24, so  in Period 4, Group 3.

(ii). Write its electron configuration

Remember that Cr is one of those exceptions to the Aufbau principle.

Instead of the predicted electron configuration of [Ar] 4s²3d⁴, we get the configuration [Ar] 4s3d⁵.

The reason is that this this configuration minimizes electron repulsion.

(b) Write the electron configuration for Cr²⁺.

Now, we must remove two electrons from a chromium atom.

The electron in the 4s orbital is removed first, because this orbital is further from the nucleus, making electrons easier to remove.

So, we remove the 4s electron, and  then a 3d electron.

The electron configuration of Cr²⁺ is

[Ar]3d⁴ or 1s² 2s²2p⁶ 3s²3p⁶ 3d⁴

(c). Electrons with n + l = 3

The orbitals with n + l = 3 are those covered by the third arrow down in the order of orbital energies:

2p (n = 2, l = 1) and 3s (n = 3, l = 0)

The 2p orbitals can hold six electrons, and the 3s orbital can hold two.

Both subshells are filled in a Cr²⁺ ion, so there are eight electrons

with n+ l = 3.

3 0
3 years ago
PLS HELP!I will give brainliest! When producing hydrogen iodide, the energy of the reactants is 581 kJ/mol, and the energy of th
Veronika [31]

Answer:

Here, we are required to determine the total energy of the reaction and determine if the reaction is an endothermic or exothermic reaction.

The correct answer is option C.

First, we need to determine the energy of the reaction.

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Hreaction = Hproduct - Hreactant.

Therefore, for the reaction above, the change in enthalpy is:

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Replacing:

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λ = 6.267x10⁻⁷m

as 1nm = 1x10⁻⁹m:

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