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Keith_Richards [23]
3 years ago
13

If HJ = 7x – 27, find the indicated values.

Chemistry
1 answer:
Sever21 [200]3 years ago
6 0
Lubos na paumanhin. maaari mo bang ipaliwanag muli ang tanong? sa totoo lang galing ako sa phillipines, masasabi mo ba sa fillipino; wika ko
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How does oxidation differ from reduction
Dima020 [189]

Answer:

See the explanation below, please.

Explanation:

In redox reactions (oxide reduction) the transfer of electrons between compounds occurs.

 In oxidation, electrons are lost (positive charge increases). Example:

Mg ---> Mg2 + + 2 e- (passes from Mg ° to Mg 2+)

On the other hand in the reduction, electrons are gained (negative charge increases or the positive one increases). Example:

Cl2 + 2e- ---> 2 Cl- + 2 e- (passes from Cl ° to Cl-)

6 0
3 years ago
Food contains a sugar called , which is broken down in a process called cellular . This process uses to break down food molecule
melisa1 [442]

Answer:

glucose

respiration

oxygen

Explanation:

4 0
3 years ago
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How to balance lead and silver acetate yields lead (||) acetate and silver
arsen [322]
The given elements put into an equation using their symbols  are as follows:
Pb + AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + Ag

Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + Ag

Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + 2AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + Ag

Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + 2AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + 2Ag

That is your final equation

The coefficients are 2 + 2 = 1 + 2
3 0
3 years ago
The VSEPR model was developed before any xenon compounds had been prepared. Thus, these compounds provided an excellent test of
Natalka [10]

The maximum amount of XeF4 that could be produced is 0.5 moles.

XeF4 = Xe (g) 2 F2 (g) (g)

Xe and F2 have a mole ratio of 1:2. Because of this, the reaction would be limited by F2 when there is 1 mole of Xe and 1 mole of F2.

<h3>What is mole ratio?</h3>

The mole ratio is the ratio of any two compounds' mole amounts that are present in a balanced chemical reaction.

A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.

A mole ratio is a conversion factor used in chemical reactions to link the mole quantities of any two compounds. A conversion factor's numbers are derived from the balanced chemical equation's coefficients.

To learn more about mole ratio from the given link:

brainly.com/question/14425689

#SPJ4

6 0
2 years ago
Using the periodic table, choose the more reactive nonmetal.<br> Te or O
jolli1 [7]

the answer is Te because O is oxygen.

5 0
3 years ago
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