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VMariaS [17]
3 years ago
14

Find the equation of the circle with center (10, 0) and point (5, 2).

Mathematics
1 answer:
Crank3 years ago
4 0

Answer:

(x - 10)² + y² = 29

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (10, 0), thus

(x - 10)² + (y - 0)² = r²

The radius is the distance from the centre to a point on the circle

Calculate r using the distance formula

r = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (10, 0) and (x₂, y₂ ) = (5, 2)

r = \sqrt{(5-10)^2+(2-0)^2}

  = \sqrt{(-5)^2+2^2}

  = \sqrt{25+4} = \sqrt{29}

Thus

(x - 10)² + (y - 0)² = (\sqrt{29} )², that is

(x - 10)² + y² = 29 ← equation of circle

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