Question

one number is 7 more than twice the other number. if the sum of the two numbers is 19, find the two numbers

Answer 1

Answer:

4 and 15

Step-by-step explanation:

Let the two numbers be a and b.

The sum of the two is 19. Therefore:

$a+b=19$

One number (let's use a) is 7 more than twice the other. Thus:

$a=7+2b$

Solve for the system of equations. Substitute the second equation into the first:

$a+b=19\\(7+2b)+b=19$

Subtract 7 from both sides:

$2b+b=12$

Combine like terms:

$3b=12$

Divide by 3:

$b=4$

So, b is 4.

And since they add up to 19, this means that a is:

$a+b=19\\a+4=19\\a=15$

So our numbers are 4 and 15

And we are done :)