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3 years ago

13

The stock market lost 777.68 points in one day. It ended at 10,364.45 points on the same day. How many points did the stock mark

et start with on that day

1 answer:

Sloan [31]3 years ago

7 0

Answer:

jnd8663393765422345678

Step-by-step explanation:

nhbkjnm.l,n aels ewdlasmjDQLKd

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Am I right?? I just need this one and another one!! need it asap! sorry if this is bothering you.

Elden [556K]

Answer:

No

Step-by-step explanation:

The correct answer is y = 3x, where y is the total cost and x is the number of pounds of oranges purchased.

5 0

2 years ago

Amelia borrows $13450 for a round-the-world trip. Her repayments are $128 per week for 3 years. How much interest is she charged

ololo11 [35]

First we need to calculate the total payments by multiplying the payment per week times number of weeks in a year times 3 years
Total payments=128×52weeks×3years
=19,968

Subtract the amount borrowed from the total payments to get the interest charged
Interest charged
=19,968−13,450=6,518

Hope it helps!

3 0

3 years ago

Find the value of two numbers if their sum is 12 and their difference is 4

Maslowich

Answer:8 and 4

Step-by-step explanation:

8+4=12

8-4=4

(hope this helps)

4 0

3 years ago

Find the unit rate please and thank you...

Gnom [1K]

Answer:

the unit rate is 1/10.

Step-by-step explanation:

4/40 divided by 4 equals 1/10

8 0

3 years ago

Read 2 more answers

Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of

Kruka [31]

Answer:

Lola was in lead for $\frac{6}{25}$ of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

$\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}$

$\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}$

$\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}$

$\text{Fraction for which Lola was in lead}=\frac{6}{25}$

Therefore, Lola was in lead for $\frac{6}{25}$ of a mile.

7 0

4 years ago