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nalin [4]
3 years ago
9

Please Help me!!!!!! Its my last question!

Mathematics
1 answer:
Strike441 [17]3 years ago
3 0
The reasonable answer is D makes since
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Find the height of a square pyramid that has a volume of 8 cubic feet and a base length of 2 feet. . . a. 6 feet. b. 16 feet. c.
exis [7]
Volume a square pyramid is expressed as the one third of the product of the base area and the hight of the shape.

Volume = (1/3)*(base area)* height

Substituting the given values, we have:

(1/3)*(2 * 2) * h = 8

h = 8*3 / (2 * 2)

h = 6 ft

Therefore, the correct answer among the choices is option A.
3 1
4 years ago
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What would D,E, I need help with these questions
Ilia_Sergeevich [38]

Answer:

D - 43°

E - 43°

Step-by-step explanation:

In squares all sides are equal, which means one of these angles are given and neither one leave the square, so 43° would be the degree of each angle inside this square.

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3 years ago
Round $4.39 to the nearest dollar
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It would be 4 dollars
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3 years ago
Find the distance between the pair of points,(9, 3), (9,7)Set up the problem here:
Lostsunrise [7]

We are given the following two points.

\mleft(9,3\mright)\: and\: (9,7)

Let us find the distance between these two points.

Recall that the distance formula is given by

undefined

3 0
1 year ago
A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the
LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1

The probability that at most 12 ties are too tight is P=1.

5 0
3 years ago
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