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konstantin123 [22]
3 years ago
5

Find the midpoint of CH if C has coordinates (-5,-2) and H has coordinates (9,-4)

Mathematics
2 answers:
Sati [7]3 years ago
8 0

Answer:

(2,1)

Step-by-step explanation:

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-5,\:-2\right),\:\left(x_2,\:y_2\right)=\left(9,\:4\right)\\\\=\left(\frac{9-5}{2},\:\frac{4-2}{2}\right)\\\\= (\frac{4}{2} , \frac{2}{2} )\\\\=\left(2,\:1\right)

KatRina [158]3 years ago
8 0
(2,1) that’s the right answer
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A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa
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Answer:

z= \frac{85-70}{10}=1.5

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So then the correct answer for this case is:

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Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

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The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

E(X)= \mu =70, SD_X=\sigma=10  

The z score is given by:

z=\frac{x-\mu}{\sigma}

If we use this we got:

z= \frac{85-70}{10}=1.5

Let Y the random variable that represent the scores for his friend, and for this case we know that:

E(Y)= \mu =35, SD_Y=\sigma=5  

The z score is given by:

z=\frac{y-\mu}{\sigma}

If we use this we got:

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

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