Answer:
sorry that was my brother
Well, a distance-preserving transformation is called a rigid motion, and the name suggests that it <em>moves the points of the plane around in a rigid fashion.</em>
A transformation is distance-preserving if the distance between the images of any two points and the distance between the two original points are equal.
If that's confusing, I get it; basically if you transform something, the points from the transformation are image points. Take the distance from a pair of image points, and take the distance from a pair of original points, and they should be the same for a <em>rigid </em>motion.
I keep emphasizing this b/c not all transformations preserve distance; a dilation can grow or shrink things. But if you didn't go over dilations, don't say nothin XD
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Answer:
range: 5 ≤ f(x) ≤ 205
Step-by-step explanation:
You can put the extreme values of x in this linear function to see its range:
f(0) = 4·0 +5 = 5
f(50) = 4·50 +5 = 205
The range is 5 ≤ f(x) ≤ 205.
1. 3x-6+2x+108+88=360
5x=170
x=34
2. figure B
Answer:
P = 42.84 cm
Step-by-step explanation:
A half-circle is joined to an equilateral triangle with side lengths of 12 units.
We need to find the perimeter of the resulting shape.
The perimeter of the half cirle is πr.
The diameter of the circle is 12. It means radius is 6 units.
An equilateral triangle has 3 equal sides. So, perimeter of the triangle is given by :
P = πr + 12 +12
= 3.14(6) + 24
= 42.84 cm
Hence, the perimeter of the resulting shape is 42.84 cm.
