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Morgarella [4.7K]
3 years ago
11

A square garden has a side length of 5 ft. What is the area of the garden?

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Answer:

the answer is 25 ft2

Step-by-step explanation:

iren [92.7K]3 years ago
5 0

Answer:

The answer to your question is 20 ft squared

Step-by-step explanation: when you hear the word "side length", it means that whatever the side length is on one side, then this means that the other side lengths are gonna be the same side length as well. For example, we already know that a square garden has a side length of 5 ft. So, since we are trying to the find the area of the square garden, you can either multiply the side length of the square garden by 4, or you can add the side length of the square garden 4 times, which will look like this:

5ft*4ft=20ft2

or 5ft+5ft+5ft+5ft= 20ft2

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Which statement about sqrt x- sqrt (x-5) =1 is true? x = 4 is a true solution. x = 4 is an extraneous solution. x = 9 is a true
ElenaW [278]

Answer:

x = 9 is a true solution

Step-by-step explanation:

Given:

√x - √(x - 5) = 1

This is irrational equation with next conditions:

x ≥ 0 and x - 5 ≥ 0  => x ≥ 0 and x ≥ 5 => x ≥ 5

√x - √(x - 5) = 1 => √x = 1 + √(x - 5)

now we will square both sides of equation and get:

x = x - 5 + 2 √(x - 5) + 1  => 2 √(x - 5 = x - x + 5 - 1 => 2 √(x - 5) = 4

now we will divide both sides with 2 and get:

√(x - 5) = 2

now we will square both sides of equation and get:

x - 5 = 4 => x = 4 + 5 = 9   => x = 9

since that this solution satisfies the given condition x ≥ 5 is accepted as final

x = 9

Check:

√9 - √(9 - 5) = 1  => 3 - √4 = 1  => 3 - 2 = 1  => 1 = 1   It's true

God with you!!!

3 0
3 years ago
What goes under the boxes? Help pls
slega [8]

Answer: -1/25 / -1/5 / 1/25

Step-by-step explanation:

6 0
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draw a quick picture to show the number 24. Then draw a quick picture to show 24 after you have regrouped 1 ten as 10 ones. expl
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Just draw circles and circle 10 at a time so 2 tens plus 4 is 24 
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Find the area of the surface. the part of the cylinder y^2+z^2=9 that lies above the rectangle with vertices (0,0),(4,0),(0,2),
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We can parameterize this part of the cylinder using

\mathbf s(u,v)=\langleu,3\cos v,3\sin v\rangle

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\mathrm d\mathbf S=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv
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so the area is given by the surface integral, where D denotes the part of the cylinder in question,

\displaystyle\iint_D\mathrm d\mathbf S=3\int_{v=\cos^{-1}(2/3)}^{v=\pi/2}\int_{u=0}^{u=4}\mathrm du\,\mathrm dv=6\pi

Probably less work would involve a simpler geometric approach, but it doesn't hurt to practice setting up a proper surface integral.
4 0
3 years ago
A line that includes the points (7,u) and (6,6) has a slope of -8. What is the value of u?
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8 0
4 years ago
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