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4 years ago

ABCD is a rhombus. Find x and y. m (80°

Mathematics

1 answer:

Vesnalui [34]4 years ago

8 0

Answer:

x = 80°, y = 100°

Step-by-step explanation:

In a rhombus the opposite angles are congruent and consecutive angles are supplementary, thus

x = ∠ D = 80° and

y = 180° - 80° = 100°

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Evaluate the following if x = 2, y= 3, and z = 10. <br><br><br>xyz =

allsm [11]

Xyz = 60
As
2 x 3 x 10 = 60

7 0

3 years ago

Bill has 205 in his savings account and adds 5$ per week.John has $5 in his account and adds 25 dollers per week. After six week

stiks02 [169]

Answer:

bill

Step-by-step explanation:

Bill:

205+(6x5)

205+30= 235

Bill - $235

John:

5+(25x6)

5+150=155

John - $155

So bill has more

Hope this helps

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3 years ago

43390 8 rounded to the hundred

Sliva [168]

43390/8?

that would be 5,423.75 or 5,423.8

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3 years ago

A researcher analyzed the results of her data from 30 subjects and calculated the variance of scores at 113.00. What is the stan

Alla [95]

Answer:

10.63

Step-by-step explanation:

Data provided in the question

Data = 30 subjects

The Variance of scores = 113.00

The calculation of standard deviation is shown below:-

As we know that

Variance = Standard deviation^2

Therefore,

Standard deviation = $\sqrt{variance}$

= $\sqrt{113}$

= 10.63

Therefore for computing the standard deviation we simply applied the above formula.

8 0

3 years ago

Part 2: NO LINKS!! NOT MULTIPLE CHOICE! Please help me

Dmitry_Shevchenko [17]

Answer:

(see attachment for tree diagram)

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

$\textsf{P(Head) and P(3)}=\sf \dfrac{1}{2} \times \dfrac{1}{6}=\dfrac{1}{12}$

$\textsf{P(Tail) and P(even)}=\sf \dfrac{1}{2} \times \dfrac{3}{6}=\dfrac{3}{12}=\dfrac{1}{4}$

$\textsf{P(not 6)}=\sf 1-\textsf{P(6)}=1-\dfrac{1}{6}=\dfrac{5}{6}$

$\implies \textsf{P(Head) and P(not 6)}=\sf \dfrac{1}{2} \times \dfrac{5}{6}=\dfrac{5}{12}$

As the six-sided die does not have a side labelled "7", the probability of rolling a 7 is zero.

$\implies \textsf{P(Head) and P(7)}=\sf \dfrac{1}{2} \times 0=0$

7 0

2 years ago