Answer:
(-2,-2) and (-7,1)
Step-by-step explanation:
I can't see i am trying
Answer:
The answer is 120 feet.
Step-by-step explanation:
The area of the field (A) is:
A = w · l (w - width, l - length)
It is known:
A = 12,000 ft²
l = w - 20
So, let's replace this in the formula for the area of the field:
12,000 = w · (w - 20)
12,000 = w² - 20
⇒ w² - 20w - 12,000 = 0
This is quadratic equation. Based on the quadratic formula:
ax² + bx + c = 0 ⇒
In the equation w² - 20w - 12,000 = 0, a = 1, b = -20, c = -12000
Thus:
So, width w can be either
or
Since, the width cannot be a negative number, the width of the field is 120 feet.
Answer:
Volume of rectangular prism = 10/9 inch³
Step-by-step explanation:
Given:
Size of each cube = 1/3 inch
Find:
Volume of rectangular prism
Computation:
Length of rectangular prism = 2 x [1/3]
Length of rectangular prism = 2/3 inch
Width of rectangular prism = 3 x [1/3]
Width of rectangular prism = 3/3
Width of rectangular prism = 1 inch
Height of rectangular prism = 5 x [1/3]
Height of rectangular prism = 5/3 inch
Volume of rectangular prism = Length x Width X Height
Volume of rectangular prism = [2/3] x [1] x [5/3]
Volume of rectangular prism = 10/9 inch³
Consider the function

, which has derivative

.
The linear approximation of

for some value

within a neighborhood of

is given by

Let

. Then

can be estimated to be

![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since

for

, it follows that

must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function

. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
The answer is c.use pemdas❤️