Question

The area of the region under the curve of the function f(x) = 5x + 7 on the interval [1, b] is 88 square units, where b > 1.

Answer 1

Answer:

Step-by-step explanation:

$\int\limits^b_1 {5x+7} \, dx =5b^2/2 + 7b-19/2$

We see that the area is 88

Solve the quadratic equation and get b = 5

Answer 2

We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1 

We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b 

5/2 x^2 + 7x (limits: 1, b)

substitute the limits:

5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0

solve for b

Then after solving for b, this would be your interval input with 1: [1, b].<span />