Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
$1.25
Step-by-step explanation:
0.35 x 8 = 2.80
7.20 + 2.80 = 10
10 divided by 8 = 1.25
Thank you :)
The Greatest Common factor of 14 and 18 is 2. Here is my work ~
What is 32% of 75?
Y is 32% of 75.
Equation: Y = P% * X.
Solving our equation for Y:
Y = P% * X.
Y = 32% * 75.
Converting percent to decimal:
p = 32%/100 = 0.32.
Y = 0.32 * 75 .
Y = 24.
Answer is 24.