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FinnZ [79.3K]
2 years ago
6

I need this in an equation.

Mathematics
1 answer:
Goryan [66]2 years ago
6 0
.115x = 20700

With x being the total price of the home 
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Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!!!!
djverab [1.8K]

Answer:

x+5

Step-by-step explanation:

Side is equal to sqrt area

= sqrt x^2 +10x + 25

= x+5

So one side of the square is x+5 metres

3 0
3 years ago
Read 2 more answers
Pls help I will appreciate pls
Alex

Answer:

S = (1  times 5)times 6

Step-by-step explanation:

Question 5. Because there are 6 friends and each of them gets 5. one of them gets 5 But there are 6 friends so you multiply by 6.       6 times 5 is 30

6 0
3 years ago
(2ײy²)⁰ I need help with exponents ​
balandron [24]

Answer:

1.

Step-by-step explanation:

Any real value to the power of 0 is 1.

7 0
3 years ago
Read 2 more answers
What is a car speed at 12 mile per 3 hours
Arturiano [62]
Hey there!
speed=distance/time.

s-speed

s=12/3
s=4

The speed of the car is 4 mph 

Hope this helps:) Let me know if you have any questions.
4 0
3 years ago
A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

5 0
2 years ago
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