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o-na [289]
3 years ago
7

Plz explain.This to me will brainliest.

Mathematics
1 answer:
Alex777 [14]3 years ago
8 0

\$228.75\ per\ week\\\\one-fifth\to\dfrac{1}{5}\ of\ her\ earnings\ each\ week\ is\ equal\\\\\dfrac{1}{5}\cdot\$228.75=\$45.75\\\\\text{How much money will she have saved after 2 months?}\\\\Two\ months\ it's\ 59-62\ days.\ It's\ less\ than\ 9\ weeks.\\Calculate\ for\ 8\ weeks.\\\\Therefore\ your\ answer\ is\ \$45.75\cdot8=\$366.00

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Consider the function f(x) = x^3 - 7x^2 - 2x + 14
mars1129 [50]

Answer:

There are 3 zeros, which are:

x=7,\:x=-\sqrt{2},\:x=\sqrt{2}

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14

To get the zeros of f(x), set y or f(x) =0

so

0=x^3-7x^2-2x+14

as

x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)

so

\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0

Using the zero factor principle:

\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0

solving

x-7=0

  • x=7

x+\sqrt{2}=0

  • x=-\sqrt{2}

x-\sqrt{2}=0

  • x=\sqrt{2}

Therefore, there are 3 zeros, which are:

x=7,\:x=-\sqrt{2},\:x=\sqrt{2}

8 0
3 years ago
F(x)=x^2 is vertically stretched by a factor of 2 and translated by 3 units left to create g(x). What does g(x)= ?
gavmur [86]

g(x)=-2(x+3)^2

The -2 in front is the vertical stretch.

Also, because it is going 3 units to the left, you have to put the 3 on the inside and because it is left you do the opposite and it is +3.

5 0
3 years ago
40, 10, 5/2 5/8... (fractions) is it arithmetic or geometric and what are the next two terms PLZ HELP DUE IN 10 MINS
patriot [66]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

40,\:10,\:\frac{5}{2},\:\frac{5}{8}

A geometric sequence has a constant ratio 'r' and is defined by

\:a_n=a_0\cdot r^{n-1}

Computing the ratios of all the adjacent terms

\frac{10}{40}=\frac{1}{4},\:\quad \frac{\frac{5}{2}}{10}=\frac{1}{4},\:\quad \frac{\frac{5}{8}}{\frac{5}{2}}=\frac{1}{4}

The ratio of all the adjacent terms is the same and equal to

r=\frac{1}{4}

Thus, the given sequence is a geometric sequence.

As the first element of the sequence is

a_1=40

Therefore, the nth term is calculated as

\:a_n=a_0\cdot r^{n-1}

a_n=40\left(\frac{1}{4}\right)^{n-1}

Put n = 5 to find the next term

a_5=40\left(\frac{1}{4}\right)^{5-1}

a_5=40\cdot \frac{1}{4^4}

a_5=\frac{40}{4^4}

   =\frac{2^3\cdot \:5}{2^8}

a_5=\frac{5}{2^5}

a_5=\frac{5}{32}

now, Put n = 6 to find the 6th term

a_6=40\left(\frac{1}{4}\right)^{6-1}

a_6=40\cdot \frac{1}{4^5}

a_6=\frac{40}{4^5}

    =\frac{2^3\cdot \:5}{2^{10}}

a_6=\frac{5}{2^7}

a_6=\frac{5}{128}

Thus, the next two terms of the sequence 40, 10, 5/2, 5/8... is:

  • a_5=\frac{5}{32}
  • a_6=\frac{5}{128}
7 0
3 years ago
If anyone Answer this question with POLITICALLY CORRECT answer I'll give you 25+ Points
Tresset [83]

Answer:

\sqrt[4]{x^5}

Step-by-step explanation:

A fraction exponent converts into a radical. The denominator is the index of the radical (farthest left number) and the numerator is the exponent of the base inside (the farthest right number). The base of the fraction exponent is the base number in green. To write this expression, simply the exponents into one exponent and one base.

x^{\frac{3}{4}}x^{\frac{1}{2} } =x^{\frac{3}{4}}x^{\frac{2}{4} } =x^{\frac{3+2}{4}} =x^{\frac{5}{4}}

Now convert to the radical.

x^{\frac{5}{4}} = \sqrt[4]{x^5}

8 0
3 years ago
PLZZ HELP ME
dimulka [17.4K]

Answer:

125/100 X 105 = 131.25

loan total = $131.25

3 0
3 years ago
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